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Over [174]
3 years ago
9

Solve for x. x/p³=1 NO ANSWERS CONTAINING CURSE WORDS OR YOU GET REPORTED!!!!!!!!!!!!!!

Mathematics
2 answers:
kati45 [8]3 years ago
6 0

Answer:

$\frac{x}{p^3}=1$

Multiply both sides by p^3

x=p^3

and p^3 \neq  0 otherwise, it is undefined.

AlladinOne [14]3 years ago
4 0

Answer:

Since x/p³ = 1 we can multiply the equation by p³ so x = p³.

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Answer:

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Step-by-step explanation:

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2 years ago
What is 0.66666666666 as a fraction
stellarik [79]

To turn 0.(6)=0.6666... into a fraction you should do such steps:

1 step. Set up an equation by representing the repeating decimal with a variable. Using your example, you will let x represent the repeating decimal 0.(6), so you have x=0.666... .

2 step. Identify how many digits are in the repeating pattern, or n digits. Multiply both sides of the equation from Step 1 by 10^n to create a new equation. Again, using your example, you see that the repeating pattern consists of just one digit: 6. Now multiply both sides of the equation by 10^1 = 10. Thus, you have 10x = 10 \cdot 0.666... or 10x = 6.666.....

3 step. Subtract the equation in Step 1 from the equation in Step 2. Notice that when we subtract these equations, our repeating pattern drops off. Therefore, 10x-x=6.666...-0.666...\\ 9x=6.

4 step. You now have an equation that you can solve for x and simplify as much as possible, using x as a fraction: 9x = 6. If you divide both sides by 9, you get x=\dfrac{6}{9}. When simplified, you get that x=\dfrac{2}{3}.

Answer: 0.(6)=0.666... =\dfrac{2}{3}.

8 0
3 years ago
Read 2 more answers
A cable weighing 0.6 pounds per foot is attached to a small 80-pound robot, and then the robot is lowered into a 60-foot deep we
ollegr [7]

Answer:6060 foot-pounds

Step-by-step explanation:

Given

Weight of cable(w')=0.6 pound per foot

depth of well=60 foot

weight of wrench=7 Pound

Now work done in raising monkey with wrench=w\cdot h

W_1=(80+7)\cdot 60=5220 foot-pounds

Now work done in raising rope

robot rises by climbing up the cable with one end of the cable still attached thus robot support half the weight of cable so work done

W_2==\int_{0}^{60}\frac{w'}{2}xdx

W_2=0.3\times 0.5\times  (x^2)_0^{60}

W_2=540 foot-pounds

W_{net}=5220+540=6060 foot-pounds

5 0
2 years ago
The distance around the wheel of a truck is 9.42 feet .what's the diameter of the wheel
kap26 [50]
To solve this problem, you must follow the proccedure that is shown below:

 1. You need to apply the formula for calculate the perimeter of a circle, which is:

P=2πr

 P is the perimeter of the circle (P=9.42 feet).
 r is the radius of the circle.

 2. Now, you must clear the radius "r" from P=2πr, as below:

 P=2πr
 r=P/2π

 3. When you substitute the values, you obtain:

 r=P/2π
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 4. Now, you can calculate the diameter (D):

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<span>
 What's the diameter of the wheel?

 The answer is: </span><span>2.98 feet</span>
7 0
3 years ago
A point P is moving along the curve whose equation is y = \sqrt x . Suppose that x is increasing at the rate of 4 units/s when x
Mice21 [21]

Answer:3 units/s

Step-by-step explanation:

Given

y=\sqrt{x}

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and \frac{\mathrm{d} x}{\mathrm{d} t}=4 units/s

Distance between Point P and (2,0)

P=\sqrt{(x-2)^2+(\sqrt{x}-0)^2}

P at x=3 P=2

rate at which distance is changing is

\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{\mathrm{d} \sqrt{(x-2)^2+(\sqrt{x}-0)^2}}{\mathrm{d} t}

\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{2x-3}{\sqrt{(x-2)^2+(\sqrt{x}-0)^2}}\times \frac{\mathrm{d} x}{\mathrm{d} t}

\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{2\times 3-3}{2\times 2}\times 4=3 units/s

8 0
3 years ago
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