Answer:
First box: 18
Second box: 40.5
Third box: 45
Step-by-step explanation:
9 km/m
We have m(<CBO) = (1/2) · m(<CBE) = (1/2) · ( x + z );
In the same way, m(<BCO) = (1/2) ·( x + y);
m(<BOC) = 180 - [(1/2) · ( x + z ) + (1/2) ·( x + y)] = 180 - (1/2)· ( x + x + y + z );
But, x + y + z = 180;
Then, m(<BOC) = 180 - (1/2)·( x + 180 );
Finally, m(<BOC) = 90 - (1/2)·x;
So, m(<BOC) = 90 - (1/2)·m(<BAC).
We are given the distance as a function of time:
s = 4.9 t^2 + 350
To get the velocity, we take the first derivative and
substitute the value of t = 2:
ds = 9.8 t dt
ds / dt = 9.8 t
velocity = 9.8 (2)
<span>velocity = 19.6 m/s</span>
