Answer:
0.03 is the probability that for the sample mean IQ score is greater than 103.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 100
Standard Deviation, σ = 16
Sample size, n = 100
We are given that the distribution of IQ score is a bell shaped distribution that is a normal distribution.
Formula:
Standard error due to sampling =

P( mean IQ score is greater than 103)
P(x > 103)
Calculation the value from standard normal z table, we have,

0.03 is the probability that for the sample mean IQ score is greater than 103.
I dont really know the difference between them lol; also it's a little blurry
sorry
Answer:
r=7v−12
Step-by-step explanation:
Let's solve for r.
−8−2r=−7v−7v+16
Step 1: Add 8 to both sides.
−2r−8+8=−14v+16+8
−2r=−14v+24
Step 2: Divide both sides by -2.
−2r
−2
=
−14v+24
−2
r=7v−12
32 because you add all the number the divide by the total amount witch is 19
Answer:
6q+4q²
Step-by-step explanation:
3q+3q+4q²
All you have to do is combine like terms(CLT)
3q+3q=6q
You can't combine 6q and 4q².
The end result is 6q+4q².
-hope it helps