Answer:
a) 5, 6
b) 8, 9
c) 9, 10
Step-by-step explanation:
It is useful to know the squares of small integers:
5² = 25
6² = 36
7² = 49
8² = 64
9² = 81
10² = 100
Then the problem becomes one of identifying the perfect squares the given number lies between
a) 25 < 35 < 36 ⇒ 5 < √35 < 6
b) 64 < 67 < 81 ⇒ 8 < √67 < 9
c) 81 < 93 < 100 ⇒ 9 < √93 < 10
The answer might be 258 but idk
Answer:
![x[2x - 5][3x - 4]](https://tex.z-dn.net/?f=x%5B2x%20-%205%5D%5B3x%20-%204%5D)
Step-by-step explanation:
![6x^3 - 23x^2 + 20x \\ x[6x^2 - 23x + 20] \\ \\ [x][6x^2 - 8x] - [15x + 20] \\ \\ [x]2x[3x - 4] \: -5[3x - 4] \\ \\ x[2x - 5][3x - 4]](https://tex.z-dn.net/?f=6x%5E3%20-%2023x%5E2%20%2B%2020x%20%5C%5C%20x%5B6x%5E2%20-%2023x%20%2B%2020%5D%20%5C%5C%20%5C%5C%20%5Bx%5D%5B6x%5E2%20-%208x%5D%20-%20%5B15x%20%2B%2020%5D%20%5C%5C%20%5C%5C%20%5Bx%5D2x%5B3x%20-%204%5D%20%5C%3A%20-5%5B3x%20-%204%5D%20%5C%5C%20%5C%5C%20x%5B2x%20-%205%5D%5B3x%20-%204%5D)
I am joyous to assist you anytime.
Answer:
B. 21.1 yd
Step-by-step explanation:
The perimeter of the figure is the sum of all its three sides.
Take note that the dotted line is not a side length of the figure.
The side lengths are 9 yd, 5 yd, and 7.1 yd.
Therefore, the perimeter of the figure = 9 + 5 + 7.1
Perimeter = 21.1 yd.
Also, take note of the unit of the perimeter. Unit of the perimeter would not be squared. Only area has a unit that is squarred.
Answer: $17,000 invested in bonds and $13,000 in certificate of deposit
Step-by-step explanation: let x = amount invested in bonds
y = amount invested in certificate of deposits.
According to the question, amount invested in bonds is $4000 more than the amount invested in certificate of deposits.
x = y + $4000 — (1)
Also from the question, the total money for investment is $30,000
x + y = $30,000 — (2)
By substituting eqn (1) into eqn (2), we have
y + 4000 + y = 30, 000
2y + 4000 = 30,000
2y = 30,000 - 4000
2y = 26,000
y = $ 13,000
But x + y = 30,000 where y = 13,000
x + 13, 000 = 30,000
x = 30,000 - 13,000
x = $17,000
Hence $17, 000 is invested in Bonds and $13, 000 in certificate of deposit
