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jeka94
3 years ago
15

Choice of 1 of 3 pies and choice of 1 of 3 drinks how many ways can you order

Mathematics
1 answer:
solong [7]3 years ago
8 0

Answer:

9

Step-by-step explanation:

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Tensile-strength tests were carried out on two different grades of wire rod. Grade 1 has 10 observations yielding a sample mean
earnstyle [38]

Answer:

t=\frac{(1085 -1034)-(0)}{57.646\sqrt{\frac{1}{10}+\frac{1}{15}}}=2.167

p_v =2*P(t_{23}

We see that the p value is lower than the significance level provided of 0.05 so then we have enough evidence to conclude that the true means are different at 5% of significance.

Step-by-step explanation:

Data given

n_1 =10 represent the sample size for group 1

n_2 =15 represent the sample size for group 2

\bar X_1 =1085 represent the sample mean for the group 1

\bar X_2 =1034 represent the sample mean for the group 2

s_1=52 represent the sample standard deviation for group 1

s_2=61 represent the sample standard deviation for group 2

We are assuming that the two samples are normally distributed with equal variances and that means:

\sigma^2_1 =\sigma^2_2 =\sigma^2

System of hypothesis

Null hypothesis: \mu_1 = \mu_2

Alternative hypothesis: \mu_1 \neq \mu_2

The statistic is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The degrees of freedom are given by:

n_1+n_2 -2

And the pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

Replacing we got:

S^2_p =\frac{(10-1)(52)^2 +(15 -1)(61)^2}{10 +15 -2}=3323.043

And the deviation would be:

S_p=57.646

The degrees of freedom are:

df=10+15-2=23

The statistic would be:

t=\frac{(1085 -1034)-(0)}{57.646\sqrt{\frac{1}{10}+\frac{1}{15}}}=2.167

The p value would be

p_v =2*P(t_{23}

We see that the p value is lower than the significance level provided of 0.05 so then we have enough evidence to conclude that the true means are different at 5% of significance.

6 0
3 years ago
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