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2 years ago

PLZZZZZZZZ HELP ME WITH THIS QUESTION ITS DUE TODAY THAT YOU!!! ALSO GIVE YOU BRAINLIEST

Mathematics

1 answer:

Airida [17]2 years ago

6 0

Answer:

I think she is correct..

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Match the following trigonometric ratios with the correct equation for the triangle shown below.

kotegsom [21]

Step-by-step explanation:

24²+7²=25²

576+49=625

625=625

4 0

2 years ago

Solve step - by - step.<br> 5b-1>=-11<br><br> Plz help!

maks197457 [2]

It would -2 because you have to bring over the -1 on the other side of the equal sign. so you would do -11 plus 1 and you will get -10 then you would 5b÷-10 (simplify).5b=-10
b=-2

7 0

2 years ago

Read 2 more answers

4.5*10^-8/9*10^-9 find the quotient and write it in scientific form

g100num [7]

Answer:

Step-by-step explanation:

4.5*10^-8/ 9*10^-9

1) Reduce the fraction, express 9 as a product of multiplying 4.5*2

4.5*10^-8/4.5*2*10^-9

2) Then notice the common factor of numerator and denominator( 4.5) , get rid of it in both numerator and dnominator

3) 10^-8/ 2*10^-9= 1/2*(10^-8/10^-9)= 0.5* (10^-8/10^-9)

10^-8/10^-9= 10^(-8-(-9))= 10^1=10.

so 0.5*10=5 (it is the answer written in scientific form)

3 0

2 years ago

Reeeeeeeeeeeeeeeeeeee

Juliette [100K]

start by writing the multiplication in this form

start multiplying from right to left.

$3\cdot0=0$

write the first number down

continue by multiplying the next number from right to left

$8\cdot3=24$

write the number down, since there are no more numbers to multiply for write the wole number

this means that

$80\cdot3=240$

5 0

1 year ago

Match each statement to it’s corresponding reason. Drake the items on the left to the correct location on the right PLEASE AND T

andreyandreev [35.5K]

Answer:

Step-by-step explanation:

1) $\angle AED$ and $\angle BEC$ are vertical angles

2) $\angle AED$ and $\angle BEC$ are created by intersecting lines (definition of vertical angles)

3) $\angle AED$ and $\angle AEB$ form a linear pair, $\angle AEB$ and $\angle BEC$ form a linear pair

4) $\angle AED$ and $\angle AEB$ are supplementary, $\angle AEB$ and $\angle BEC$ are supplementary

5) $\angle AED \cong \angle BEC$

6 0

1 year ago