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2 years ago

PLZZZZZZZZ HELP ME WITH THIS QUESTION ITS DUE TODAY THAT YOU!!! ALSO GIVE YOU BRAINLIEST

Mathematics

1 answer:

Airida [17]2 years ago

6 0

Answer:

I think she is correct..

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How many triangles can be constructed with sides measuring 7 cm, 6 cm, and 9 cm? more than one one none

REY [17]

Answer:

none

Step-by-step explanation:

3 0

2 years ago

A water tower casts a shadow that is 24 foot long. A 9.5 foot tall tree casts a shadow that is 8 foot long. What is the height o

sveticcg [70]

Answer:

28.5 feet

Step-by-step explanation:

A water tower casts a shadow that is 24 foot long. A 9.5 foot tall tree casts a shadow that is 8 foot long. What is the height of the water tower?

The formula is given as:

Height of the tower/Shadow of the tower = Height of the tree/Shadow of the tree

Let the Height of the tower = x

Hence:

x/24 = 9.5/8

Cross Multiply

8x = 24 × 9.5

x = 24 × 9.5/8

x = 28.5 feet

Therefore, the height of the water tower is 28.5 feet

6 0

2 years ago

Can someone help, please

Allisa [31]

Answer:

$\frac{9}{5}$

Step-by-step explanation:

the slope is the change in y over the change in x

From the points given, your y's are 10 and 1.

From the points given, your x's are 7 and 2. To find the changes subtract them.

$\frac{10-1}{7-2}$ = $\frac{9}{5}$

4 0

9 months ago

Read 2 more answers

Pat and James were building a fort. They needed to use boards that were six feet long. THe Store sold them in 12 foot boards, th

Anettt [7]

7 and a half originally they would’ve needed obviously 15 but if you divide that by two you get 7 and a half

7 0

3 years ago

Solve the following initial-value problem: cos(x) dy/dx + sin(x) y - 1 = 0, y(0) = 1

Akimi4 [234]

Answer:

y= x + cosx

Step-by-step explanation:

$cosx\frac{\mathrm{d}y }{\mathrm{d} x}+(sinx)y-1=0\\cosx\frac{\mathrm{d}y }{\mathrm{d} x}+(sinx)y=1\\\frac{\mathrm{d}y }{\mathrm{d} x}+(tanx)y=secx$

now equation is in linear differential form

finding integrating factor;

I.F. = $e^{\int tanx dx} = e^{ln\ secx} = secx$

$y=\frac{1}{I.F}(\int Q dx + c)$

$y=\dfrac{1}{secx}(\int secx dx + c)$

$y=\int dx + c(cosx)\\y= x + c(cosx)$

using y(0) = 1

1 = 0 + c(cos 0)

c = 1

hence solution becomes

y= x + cosx

4 0

2 years ago