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CaHeK987 [17]
3 years ago
10

What is the y-intercept of the polynomial f(x)f(x) f(x) defined below? Write the y-value only. f(x)=−4x2+x5+10x3+5x+8x4f(x)=-4x^

2+x^5+10x^3+5x+8x^4 f(x)=−4x 2 +x 5 +10x 3 +5x+8x 4
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
4 0

Answer:

y = 0

Step-by-step explanation:

Given

f(x) = 4x² +x⁵ +10x³ +5x+8x⁴

Required

Determine the y intercept

The y intercept of a function is a point where x = 0

So, we have to substitute 0 for x in the above function

f(x) = 4x² +x⁵ +10x³ +5x+8x⁴ becomes

f(0) = 4(0)² +(0)⁵ +10(0)³ +5(0)+8(0)⁴

f(0) = 4 * 0 + 0 + 10 * 0 + 5 * 0 + 8 * 0

f(0) = 0 + 0 + 0 + 0 + 0

f(0) = 0

Substitute y for f(0)

y = 0

Hence, the y intercept is 0

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Consider rolling two fair dice and observing the number of spots on the resulting upward face of each one. Letting A be the even
Allushta [10]

Answer:

P(E|A)= \frac{10}{11}

Step-by-step explanation:

Given

Two rolls of die

E \to one of the outcomes is 6

A \to atleast one is 6

Required

P(E|A)

First, list out the outcome of each

E = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}

A = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}

So:

P(E|A)= \frac{n(E\ n\ A)}{n(A)}

Where:

E\ n\ A = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}

n(E\ n\ A) = 10

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So:

P(E|A)= \frac{10}{11}

7 0
3 years ago
5. Find the general solution to y'''-y''+4y'-4y = 0
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For any equation,

a_ny^(n)+\dots+a_1y'+a_0y=0

assume solution of a form, e^{yt}

Which leads to,

(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0

Simplify to,

e^{yt}(y^3-y^2+4y-4)=0

Then find solutions,

\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}

For non repeated real root y, we have a form of,

y_1=c_1e^t

Following up,

For two non repeated complex roots y_2\neq y_3 where,

y_2=a+bi

and,

y_3=a-bi

the general solution has a form of,

y=e^{at}(c_2\cos(bt)+c_3\sin(bt))

Or in this case,

y=e^0(c_2\cos(2t)+c_3\sin(2t))

Now we just refine and get,

\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}

Hope this helps.

r3t40

5 0
4 years ago
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