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jolli1 [7]
3 years ago
5

What is the solution to this equation?

Mathematics
1 answer:
Dafna11 [192]3 years ago
8 0

Answer:

m= -1/2

this is the answer

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decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring. −b b2 − 4ac 2a u
Romashka [77]

Answer:

Step-by-step explanation:

A quadratic equation can be factorised if and only if there are rational roots.

For any quadratic equation the discriminant decides about the nature of roots.

Thus only if the discriminant is a perfect square we can have rational roots and in this case only factorization is possible.

In the given equation

2x^2+ 7x+ 3 = 0\\a=2, b=7, c=3\\b^2-4ac = 1

Since 1 is a perfect square we can factor and solve

2x^2 +7x +3 = 0\\(2x+1)(x+3)=0\\x=-1/2 or x = -3

4 0
3 years ago
Read 2 more answers
-3(×+2)=12 what is x equal to
velikii [3]

Answer:

x=-6

Step-by-step explanation:

Follow along:

1. Distribute the -3 to those within the parenthesis.

-3x-6=12

2. Move the whole numbers to one sides, isolate the variable.

-3x=18

3. Divide both sides by -3

x=-6

7 0
3 years ago
Place the following scenarios in order by the size of their probability, largest to smallest.
IrinaK [193]

Answer:

3, 1, 2, 4

Step-by-step explanation:

i am not sure but i think this is it

7 0
3 years ago
How is 340 divided by 17 reasonable
vivado [14]
17 goes into 34 two times

and goes into 0 zero times

So 340 / 17 = 20
8 0
3 years ago
Read 2 more answers
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
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