Answer:
c) 0.932
99% confidence interval for average weights of all packages sold in small meat trays.
(0.932 ,1.071)
Step-by-step explanation:
Explanation:-
Given random sample of 35 packages in small meat trays produced weight with an average of 1.01 lbs. and standard deviation of 0.18 lbs.
size of the sample 'n' = 35
mean of the sample x⁻= 1.01lbs
standard deviation of the sample 'S' = 0.18lbs
<u>The 99% confidence intervals are given by</u>

The degrees of freedom γ=n-1 =35-1=34
tₐ = 2.0322
99% confidence interval for average weights of all packages sold in small meat trays

( 1.01 - 0.06183 , 1.01+0.06183)
(0.932 ,1.071)
<u>Final answer</u>:-
<u>99% confidence interval for average weights of all packages sold in small meat trays.</u>
<u>(0.932 ,1.071)</u>
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Answer:
I think the closest would be 41.5%
Step-by-step explanation:
If you take the number of passengers left on the plane and divide by the total number of passengers that were on the plane in the beginning, you would get 58.5%. That's the % of how many people are left on the plane. So, you would then do 100%-58.5% to get the answer 41.5%. Hope this helps! :)
Probability is defined as the <u>likelihood or the certainty</u> that an event is going to<u> occur or happen.</u>
The probability of randomly choosing a red and then a green marble is
.
The total number of marbles = 20
The number of green marbles= 3
The number of blue marbles = 12
The number of red marbles = 5
<u>The probability of choosing a red marble</u> = Number of red marbles / Total number of marbles
= 5/20
<u>In simplest fraction form</u> = 
We are told in the question that you keep the red marble you choose, So this means the <u>total number of marbles</u> left reduces to 19
<u>The probability of choosing a green marble is</u> = Number of green marbles / New total number of marbles
= 3/19
Therefore, <u><em>the probability of randomly choosing a red and then a green marble is </em></u>
P (Red) x P(Green)
= 1/4 x 3/19
= 
To learn more, visit the link below:
brainly.com/question/22563776