3 years ago

The average value of sqrt 3x on the closed interval [0,9] is?

1 answer:

8 0

To answer the question above, we have to use this equation. This problem is simple,
<span>fAV = ∫ √(3x) dx/(9 - 0) = ∫ (3x)^(1/2)
then simplify the equation
dx/9 = 31.17691497../9 ≈
Then the answer would be.
3.464
I hope I helped you with your problem. Have a nice day</span>

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