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beks73 [17]
3 years ago
12

Whats the greatest common factor of ..

Mathematics
2 answers:
Flauer [41]3 years ago
6 0
1.
-60r^2s^2t^2 = 15r^2t^2(-4s^2)<span>
and
45r^3t^3 = 15</span>r^2t^2(rt)

answer: GCF = 15r^2t^2

<span>2.
32m^2n^3 = 2</span>m^2n^2(16n)<span>
and
18m^2n^2 =</span> 2m^2n^2(9)<span>
and
56m^3n^2</span> = 2m^2n^2(28m)
so
answer GCF = 2m^2n^2
Katarina [22]3 years ago
4 0
<span>he rule of 78,the amount of unearned interest (finance charge that need not be paid) is given bywhere u is the amount of ...

</span>
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Consider the following probability distribution function of the random variable X which represents the number of people in a gro
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(a) 3.55

(b) 3.45 and 1.86

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The random variable <em>X</em> denotes the number of people in a group (party) at a restaurant.

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The formula to compute the mean is:

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Consider the Excel sheet attached.

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(b)

The formula to compute the variance is:

\sigma^{2}=[\sum {x^{2}\cdot P(X=x)}]-(\mu)^{2}

Consider the Excel sheet attached.

Compute the variance as follows:

\sigma^{2}=[\sum {x^{2}\cdot P(X=x)}]-(\mu)^{2}\\\\=16.05-(3.55)^{2}\\\\=3.4475\\\\\approx 3.45

The variance is, 3.45.

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The standard deviation is, 1.86.

(c)

Compute the probability that the next party will be over 4 people as follows:

P(X>4)=P(X=5)+P(X=6)+P(X=7)+P(X=8)\\\\=0.10+0.05+0.05+0.05\\\\=0.25

Thus, the probability that the next party will be over 4 people is 0.25.

(d)

Compute the probability that the next three parties will each be over 4 people as follows:

It is provided that the three parties are independent.

P (Next 3 parties will be each over 4) = [P (X > 4)]³

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Thus, the probability that the next three parties will each be over 4 people is 0.016.

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