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3 years ago

How do you find the surface area of a pyramid

Mathematics

1 answer:

alukav5142 [94]3 years ago

8 0

Answer:

We can find the surface area of any pyramid by adding up the areas of its lateral faces and its base.

Surface area of any pyramid = area of base + area of each of the lateral faces

Example:A=lw+l(w2)2+h2+w(l2)2+h2=3·2+3·(2

2)2+82+2·(3

2)2+82≈46.46559

Step-by-step explanation:

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Pleaase help!<br>Find h. 11 in. h = ✓ [?] in. 14 in Enter

Aleksandr [31]

Answer:

$h=8.48\ \text{inches}$

Step-by-step explanation:

Given that,

Radius of cone, r = 7 inches

Slant height of the cone, l = 11 inches

We need to find the height of the cone. Let the height be h. Using trigonometry to find it as follows :

$h^2+r^2=l^2\\\\h=\sqrt{l^2-r^2}\\\\h=\sqrt{11^2-7^2}\\\\h=8.48\ \text{inches}$

So, the height of the cone is equal to $8.48\ \text{inches}$ .

3 0

3 years ago

Mary is putting money into a checking account. Let y represent the total amount of money in the account (in dollars). Let x repr

vova2212 [387]

So mary is putting 30 dollars a week into a savings account. The y-intercept is 750 which means that before she started putting money she had 750 dollars.

The change per week is 30 dollars increase.
The starting amount is 750 dollars.

I hope this answers your question. If not, comment below!

4 0

4 years ago

Major help please :)

Zielflug [23.3K]

Answer:

Step-by-step explanation:

$(\frac{x}{y} )^{a} = \frac{x^{a}}{y^{a}}$

$(\frac{-11}{14} )^{5} = \frac{(-11)^{5}}{14^{5}}$

6 0

4 years ago

If a town with a population of 10,000 doubles every 14 years, what will the population be in 42 years and is it modeled by a lin

madreJ [45]

This is an exponential function.
The starting population is: 10,000 and it doubles every 14 years.
In 42 years ( 42 : 14 = 3 ) the population doubles 3 times.
The equation ( exponential ) is :
y = 10,000 * 2^n
In this case: n = 3
y = 10,000 * 2 ^3 = 10,000 * 8 = 80,000
Answer: In 42 years the population of this town will be 80,000.

5 0

3 years ago

Read 2 more answers

Two random samples are taken from private and public universities

kati45 [8]

Answer:

Step-by-step explanation:

For private Institutions,

n = 20

Mean, x1 = (43120 + 28190 + 34490 + 20893 + 42984 + 34750 + 44897 + 32198 + 18432 + 33981 + 29498 + 31980 + 22764 + 54190 + 37756 + 30129 + 33980 + 47909 + 32200 + 38120)/20 = 34623.05

Standard deviation = √(summation(x - mean)²/n

Summation(x - mean)² = (43120 - 34623.05)^2+ (28190 - 34623.05)^2 + (34490 - 34623.05)^2 + (20893 - 34623.05)^2 + (42984 - 34623.05)^2 + (34750 - 34623.05)^2 + (44897 - 34623.05)^2 + (32198 - 34623.05)^2 + (18432 - 34623.05)^2 + (33981 - 34623.05)^2 + (29498 - 34623.05)^2 + (31980 - 34623.05)^2 + (22764 - 34623.05)^2 + (54190 - 34623.05)^2 + (37756 - 34623.05)^2 + (30129 - 34623.05)^2 + (33980 - 34623.05)^2 + (47909 - 34623.05)^2 + (32200 - 34623.05)^2 + (38120 - 34623.05)^2 = 1527829234.95

Standard deviation = √(1527829234.95/20

s1 = 8740.22

For public Institutions,

n = 20

Mean, x2 = (25469 + 19450 + 18347 + 28560 + 32592 + 21871 + 24120 + 27450 + 29100 + 21870 + 22650 + 29143 + 25379 + 23450 + 23871 + 28745 + 30120 + 21190 + 21540 + 26346)/20 = 25063.15

Summation(x - mean)² = (25469 - 25063.15)^2+ (19450 - 25063.15)^2 + (18347 - 25063.15)^2 + (28560 - 25063.15)^2 + (32592 - 25063.15)^2 + (21871 - 25063.15)^2 + (24120 - 25063.15)^2 + (27450 - 25063.15)^2 + (29100 - 25063.15)^2 + (21870 - 25063.15)^2 + (22650 - 25063.15)^2 + (29143 - 25063.15)^2 + (25379 - 25063.15)^2 + (23450 - 25063.15)^2 + (23871 - 25063.15)^2 + (28745 - 25063.15)^2 + (30120 - 25063.15)^2 + (21190 - 25063.15)^2 + (21540 - 25063.15)^2 + (26346 - 25063.15)^2 = 1527829234.95

Standard deviation = √(283738188.55/20

s2 = 3766.55

This is a test of 2 independent groups. Let μ1 be the mean out-of-state tuition for private institutions and μ2 be the mean out-of-state tuition for public institutions.

The random variable is μ1 - μ2 = difference in the mean out-of-state tuition for private institutions and the mean out-of-state tuition for public institutions.

We would set up the hypothesis. The correct option is

-B. H0: μ1 = μ2 ; H1: μ1 > μ2

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

t = (34623.05 - 25063.15)/√(8740.22²/20 + 3766.55²/20)

t = 9559.9/2128.12528473889

t = 4.49

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [8740.22²/20 + 3766.55²/20]²/[(1/20 - 1)(8740.22²/20)² + (1/20 - 1)(3766.55²/20)²] = 20511091253953.727/794331719568.7114

df = 26

We would determine the probability value from the t test calculator. It becomes

p value = 0.000065

Since alpha, 0.01 > than the p value, 0.000065, then we would reject the null hypothesis. Therefore, at 1% significance level, the mean out-of-state tuition for private institutions is statistically significantly higher than public institutions.

4 0

3 years ago