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aleksley [76]
3 years ago
10

Which of these methods is NOT solely applicable to biological classifications?

Biology
2 answers:
zvonat [6]3 years ago
8 0
B. Cladistics, because the other two choices don't make any sense.
Korolek [52]3 years ago
7 0

Answer:

Option B, Cladistics

Explanation:

In a biological classification system, organisms are grouped into different groups based on the similarity of physical (as per traditional classification systems) and genetic characteristics (as per modern classification systems).  

Whittaker has grouped the organisms into five kingdoms - Monera, Protista, Fungi, Plantae and Animalia based on their cellular structure, reproduction, feeding pattern and many other physical characteristics.  

However, Linnaeus’s classification group organisms into eight texas which are as follows -domain, kingdom, phylum, class, order, family, genus, and species.

However, Cladistics involves development of cladograms which are more or less similar to phylogenetic trees. Caldograms group organism based on the shared ancestry and descendants at each clade (group of organism also including ancestor species)

Hence, option B is correct

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1. Galactosemia is a disease that will only be expressed when a person is<span><span><span> homozygotic recessive for that trait. It's the same as saying it </span> has</span> 2 recessive alleles.

Dominant allele-</span><span> G
recessive allele- g
</span>
Homozygotic dominant:  GG <span><span>(doesn't express the disease)
</span>Heterozygotic : Gg (doesn't express the disease)
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2.
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</span>- If his mother is GG, one of these G's is going to be passed to Justin. So, his genotype is either GG or Gg. Since we are not sure we write as: G_.
Justin's genotype: G_

3.
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Justin's uncle has galactosemia so his genotype is: gg

-
If the uncle was able to receive two recessive alleles it means the mother had one to pass, and so did the father. However, in the diagram, it's not pointed out that they have a disease so it only leaves one possible genotype: Gg. Justin's grandparents are both Gg.

4. The last person to analyze is Justin's father.
If we crossed the grandparents (Gg x Gg) we could obtain these genotypes: GG, Gg, gg.
Justin's father doesn't express the trait, so it's not gg. That leaves us with either GG or Gg. Since we can't know for sure, onece again we write as G_
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