Seventeen-thousand and one hundred 6 thousandths written in standard form would be 17,000.106
Hope this helped =)
Multiply the first equation by -2 gives:_
-2y = -8 + 2x
2y = 8 - 2x
adding these 2 equations:-
0 = 0
This shows that the 2 equations are equal so there are infinite solutions
4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
Step-by-step explanation:
2x+3=x+x+3
add the X's on the right side together.
2x+3=2x+3
subtract 2x from both sides
3=3
subtract 3 from both sides
0=0
the statement is true for any value of x
Answer:
The answer is x=9 and/or x = -12
Step-by-step explanation:
This is a quadratic formula meaning that you must take the a value (1) b value (3) and the c value (108) and plug it into the quadratic formula.
which simplifies to -3 add or subtract the sqrt of 441 divided by two.
