Answer:
The area of the triangle is ![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
Step-by-step explanation:
Given:
Coordinates D (0, 0), E (1, 1)
Angle ∠DEF = 60°
△DEF is a Right triangle
To Find:
The area of the triangle
Solution:
The area of the triangle is = ![\frac{1}{2}(base \times height)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28base%20%5Ctimes%20height%29)
Here the base is Distance between D and E
calculation the distance using the distance formula, we get
DE = ![\sqrt{(0-1)^2 + (0-1)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%280-1%29%5E2%20%2B%20%280-1%29%5E2%7D)
DE =![\sqrt{(-1) ^2 + (-1)^2](https://tex.z-dn.net/?f=%5Csqrt%7B%28-1%29%20%5E2%20%2B%20%28-1%29%5E2)
DE = ![\sqrt{1+1}](https://tex.z-dn.net/?f=%5Csqrt%7B1%2B1%7D)
DE = ![\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D)
Base = ![\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D)
Height is DF
DF =![tan(60^{\circ}) \times DE](https://tex.z-dn.net/?f=tan%2860%5E%7B%5Ccirc%7D%29%20%5Ctimes%20DE)
DF = ![\sqrt{3} \times DE](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D%20%5Ctimes%20DE)
DF = ![\sqrt{3} \times\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D%20%5Ctimes%5Csqrt%7B2%7D)
Now, the area of the triangle is
= ![\frac{1}{2}({\sqrt{2})(\sqrt{3} \times \sqrt{2})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%7B%5Csqrt%7B2%7D%29%28%5Csqrt%7B3%7D%20%5Ctimes%20%5Csqrt%7B2%7D%29)
=![\frac{1}{2}({\sqrt{2})(\sqrt{3} \sqrt{2})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%7B%5Csqrt%7B2%7D%29%28%5Csqrt%7B3%7D%20%5Csqrt%7B2%7D%29)
=![\frac{1}{2}(2\sqrt{3} )](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%282%5Csqrt%7B3%7D%20%29)
=![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
i think C but i dont know forsure
One way to do it is you can draw two sets of 7/8.
You can draw 8 tiles, and color in 7.
Draw that two times.
That’s one way, but that might not be the way you learned it.
Hope this helped anyways!
Answer:
A
Step-by-step explanation:
In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. This altitude divides the triangle into two right triangles ADC and BDC. In these triangles,
So,
![\triangle ABC\sim \triangle CBD\sim \triangle ACD](https://tex.z-dn.net/?f=%5Ctriangle%20ABC%5Csim%20%5Ctriangle%20CBD%5Csim%20%5Ctriangle%20ACD)
1. From the similarity
you have
![\dfrac{AB}{BC}=\dfrac{BC}{BD}\\ \\\dfrac{c}{a}=\dfrac{a}{s}](https://tex.z-dn.net/?f=%5Cdfrac%7BAB%7D%7BBC%7D%3D%5Cdfrac%7BBC%7D%7BBD%7D%5C%5C%20%5C%5C%5Cdfrac%7Bc%7D%7Ba%7D%3D%5Cdfrac%7Ba%7D%7Bs%7D)
2. From the similarity
you have
![\dfrac{AB}{AC}=\dfrac{AC}{AD}\\ \\\dfrac{c}{b}=\dfrac{b}{r}](https://tex.z-dn.net/?f=%5Cdfrac%7BAB%7D%7BAC%7D%3D%5Cdfrac%7BAC%7D%7BAD%7D%5C%5C%20%5C%5C%5Cdfrac%7Bc%7D%7Bb%7D%3D%5Cdfrac%7Bb%7D%7Br%7D)
Hence, option A is true
Let
x--------> the number of children
y------> the number of teenagers
z------> the number of adults
we know that
------> equation A
-----> equation B
![y=\frac{3}{4}x](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B3%7D%7B4%7Dx)
-------> equation C
Substitute equation C in equation A and equation B
![2[\frac{4}{3}y]+3y+5z=1,950](https://tex.z-dn.net/?f=2%5B%5Cfrac%7B4%7D%7B3%7Dy%5D%2B3y%2B5z%3D1%2C950)
--------> equation D
![[\frac{4}{3}y]+y+z=570](https://tex.z-dn.net/?f=%5B%5Cfrac%7B4%7D%7B3%7Dy%5D%2By%2Bz%3D570)
--------> equation E
Multiply equation E by ![-5](https://tex.z-dn.net/?f=-5)
--------> equation F
Adds equation D and equation F
![\frac{17}{3}y+5z=1,950\\\\-\frac{35}{3}y-5z=-2,850\\\\---------\\\\-\frac{18}{3}y=-900\\\\y=3*900/18\\\\y=150\ teenagers](https://tex.z-dn.net/?f=%5Cfrac%7B17%7D%7B3%7Dy%2B5z%3D1%2C950%5C%5C%5C%5C-%5Cfrac%7B35%7D%7B3%7Dy-5z%3D-2%2C850%5C%5C%5C%5C---------%5C%5C%5C%5C-%5Cfrac%7B18%7D%7B3%7Dy%3D-900%5C%5C%5C%5Cy%3D3%2A900%2F18%5C%5C%5C%5Cy%3D150%5C%20teenagers)
therefore
<u>the answer is the option</u>
![150\ teenagers](https://tex.z-dn.net/?f=150%5C%20teenagers)