Answer:
0.918 is the probability that the sample average sediment density is at most 3.00
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 2.80
Standard Deviation, σ = 0.85
Sample size,n = 35
We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.
Formula:
Standard error due to sampling:
P(sample average sediment density is at most 3.00)
Calculation the value from standard normal z table, we have,
0.918 is the probability that the sample average sediment density is at most 3.00
Answer:
Delta does not have a relative extreme in the equation, so it is variable y It can not be true
Step-by-step explanation:
There is an answer
The rest of the equation that has no substituted delta is not true, so the prime variables have relative extremes.
26,862 divided by 407 is 66
Here's the long division way that shows how you get 66
Answer:
$88
Step-by-step explanation:
To find the increase of $80 by 10%, find 10% of $80 then add it by the original amount
10% of 80=80*0.1=$8
The original amount=$80
Total amount=$80+$8=$88
Answer:
The means is 8.5 The Median is 6
Step-by-step explanation:
1) to find the mean just Simply add all the numbers together and divided by how many numbers that is giving. (Because you are simply finding the average)
9+6+5+3+28+6+4+7=68
68 divided by 8 = 8.5
2) to find the median simply organize the numbers from least to greatest Like this: (3,4,5,6,6,7,9,28) Then keep crossing out from both sides teal you find the middle Number.
If there a odd amount of number the median will be one Number, if even 2 numbers ( if 2 numbers just add them both and divide by 2)
In This Case the Median is 6,6 but Its actually 6 Why (6+6=12) and (12/2=6) so your median is 6.
<em>Hopes This helps!</em>
