For T = 89.5 degrees C:
E(t) = 1100(90 - 89.5) + 520(90 - 89.5)^2= 1100(0.5) + 520(0.5)^2= 550 + 130= 680 m
For T = 90 degrees C:
E(t) = 1100(90 - 90) + 520(90 - 90)^2= 0 + 0= 0 m (meaning that boiling point is 90 degrees C at ground level)
Answer:
1.5 batches take 12.375 hour
Step-by-step explanation:
The first batch takes 10.5 hours, meaning only .5 batches are left. You then take the time that each new full batch takes (4.25) and divide it by 2 as you only need half of one batch. Meaning 0.5 of a batch takes 2.125 hours. You then take the time of the two batches (10.5, and 2.125) and add them, leaving you with 12.625. Meaning 12.375 is the most viable answer.
Answer:
cot∅ = (-2√30)/7.
Step-by-step explanation:
Given the value of csc∅ = -13/7 and ∅ is in quad III.
We know y = r sin∅ and r > 0. So csc∅ = r/y = -13/7 = 13/(-7).
It means y = -7, r = 13.
We know x² + y² = r².
x² = r² - y²
x² = (13)² - (-7)² = 169 - 49 = 120.
x = √120 = 2√30.
we know cot∅ = x/y = (2√30)/(-7) = (-2√30)/7.
Hence, cot∅ = (-2√30)/7.
Answer:
Step-by-step explanation:
It's solved by grafic method
