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sergey [27]
3 years ago
12

Given three consecutive integers with a sum of four times the second number, write an algebraic equation for this situation

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
5 0
<u>Define x:</u>

Let the first number be x.

1st number = x
2nd number = x + 1
3rd number = x + 2

<u>Construct equation:</u>
x + x + 1 + x + 2 = 4(x + 1)
3x + 3 = 4(x + 1)

Answer: 3x + 3 = 4(x + 1)
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twice a number plus another number is 310. The difference between the two numbers is 55. What are the two numbers
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T us assume the two numbers to be "x" and "y".
Then
2x + y = 310
And
x - y = 55
Let us take the second equation and find the value of x in relation to y.
x - y = 55
x = y + 55
Now let us put the value of x in the first equation, we get
2x + y = 310
2(y + 55) + y = 310
2y + 110 + y = 310
3y = 310 - 110
3y = 200
y = 200/3
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Now putting the value of y in the second equation, we get
x - y = 55
x - (200/3) = 55
3x - 200 = 55 * 3
3x = 165 + 200
x = 365/3
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So the value of x is 121 2/3 and the value of y is 66 2/3

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Given that (9,-8) is on the graph of f(x), find the corresponding point for the function f(x-2)
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