1) -3x -3 -7x = 17
• start by grouping so add -3x and -7x which gives you -10x
• 10x -3 (+3) = 17 +3 = 20 add 3 on both sides)
• 10x (/10) = 20/ 10 = 2
1) x = 2

2) 10x -6 (+6) = 24 + 6 = 30
• 10x (/10) = 30/ 10 = 3
2) x = 3

3) -4 (+4) -5x = -39 +4 = -35
• -5x (/-5) = -35/ -5 = 7
3) x = 7

4) 3x - 5 > 10
this one i don’t understand, is there a typo maybe ?

5) -5x + x + 16 = -3 you can put a 1 to hold the place of x to make it 1x
• (-5x + 1x) + 16 = -3
• -4x + 16 (-16) = -3 -16 = -19
• -4x (/-4) = -19/ -4 = 4.75 or 4 3/4
5) x = 4.75

6 0

2 years ago

Find the area of a square if its sides measure 2 2/3m

olga55 [171]

Answer:

$7\dfrac{1}{9}\ m^2$

Step-by-step explanation:

If the length of the square side is a units, then the area of the square is

$A=a^2\ un^2.$

In your case, the side length is

$a=2\dfrac{2}{3}\ m,$

then the area is

$A=2\dfrac{2}{3}\cdot 2\dfrac{2}{3}\\ \\ \\A=\dfrac{2\cdot 3+2}{3}\cdot \dfrac{2\cdot 3+2}{3}\\ \\ \\A=\dfrac{8}{3}\cdot \dfrac{8}{3}\\ \\ \\A=\dfrac{64}{9}\\ \\ \\A=7\dfrac{1}{9}\ m^2$

6 0

3 years ago

From the top of a 100-ft building a man

romanna [79]

Answer:

219m

Step-by-step explanation:

Since the man observes the car with angle 15 before observing in 33 degrees.

For the first observation

The angle observation gives an angle if 33 degrees with the horizontal.

It gives a triangle which I'll attach to the que,

from the first triangle

Tan 33 = 100/y

Y= 100/ tan 33

Y = 153.99m.

This is the distance from the building to the distance where it was secondly observed( 33).

To find x

tan 15 = 100/(153.99+x)

153.99 + x = 100/ tan 15

153.99 + x = 373.21

The distance between the two observed angles

X= 219m.

5 0

3 years ago