All categories

3 years ago

Write an equivalent exponential equation for the following three problems.

Mathematics

1 answer:

Naily [24]3 years ago

8 0

<u>Answer with step-by-step explanation:</u>

We are given three different expressions and we are to write an equivalent exponential equation for them.

We know that the standard form of a logarithmic expression is given by:

$y = log_a ( x )$ which is equivalent to the exponential form $x = a ^ y$ .

1. $log _ {10} (0.1) = -1$ ---> $10^{-1}=0.1$

2. $log _ {3} 9 = 2$ ---> $3^2=9$

3. $log _ 5 ( \frac { 1 } { \sqrt { 5 } } ) = -\frac { 1 } { 2 }$ ---> $5^{-\frac{1}{2} }=\frac{1}{\sqrt{5} }$

You might be interested in

Someone please help I genuinely don’t understand

mart [117]

Answer:

Step-by-step explanation:

2) l = 9 cm

b = 7 cm

h = 3 cm

Surface Area= 2*(lb + bh + hl)

=2*(9*7 + 7*3 + 3*9)

=2*(63 + 21 + 27)

= 2 * 111

= 222 cm²

7 0

3 years ago

Can you please help?

Liula [17]

Answer:

$\huge\boxed{3.873}$

Step-by-step explanation:

Note that the squares are on the sides of these triangles are on the hypotenuse/one leg.

We know that the area of a square is $l^2$ where l is the length. Since we know the area, we can find the square root of the area to find the side length.

So the side lengths are $\sqrt{25}$ and $\sqrt{10}$ .

Since we know the hypotenuse is $\sqrt{25}$ and one of the legs is $\sqrt{10}$ , we can use the Pythagorean Theorem to find the missing side.

The Pythagorean Theorem states that $a^2 + b^2 = c^2$ , where c is the hypotenuse and a/b are the legs.

We know the <em>hypotenuse </em>and <em>a leg</em>, so we can substitute inside

$a^2 + \sqrt{10}^2 = \sqrt{25}^2$

Squaring a square root is the same as doing nothing.

$a^2 + 10 = 25\\\\a^2 = 25-10\\\\a^2 = 15\\\\a = \sqrt{15}\\\\a \approx 3.873$

Hope this helped!

7 0

4 years ago

Write 25.74 in word form

arlik [135]

<h3>Hey there! </h3><h3> $Problem : \boxed{25.74}$ </h3><h3>Anything that is possibly $behind$ the $decimal$ usually ends with " $th$ " </h3><h3>Since there is no number $behind$ the number $7$ we know that the $74$ would be labeled as the " $hundredths$ " $25$ would simply be $twenty-$ $five$ </h3><h3>Therefore, your $answer$ → $twenty-$ $five$ $and$ $seventy-$ $four$ $hundredths$ </h3><h3>Good luck on your assignment and enjoy your day! </h3><h3>~ $LoveYourselfFirst:)$ </h3>

5 0

3 years ago

1x+1y=5 graph and y-intercept form

Stels [109]

If x+y=5, let y = 0 to find the x-intercept: x=5. The x-int. is at (5,0).
Let x = 0 to find the y-int: y=5. The y-int is (0,5).

Plot (5,0) and (0,5), and then draw a straight line thru both points.

If x+y=5, solving for y results in y = -1x + 5
Comparing this to y = mx + b, m=-1 and b= 5. Again, the y-int. is (0,5).

7 0

3 years ago

Find the area of the shape shown below.

miskamm [114]

Answer:

28 units^2

Step-by-step explanation:

1. First, let's divide this figure into two shapes: a square and a trapezoid. (Look at the image below explanation for division).

2. Next, we should know the area formulas of the square and trapezoid.