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Natasha_Volkova [10]
3 years ago
8

Written equation for y=-2=1 (0,3)

Mathematics
1 answer:
Alika [10]3 years ago
4 0
Is that supposed to be y=-2x+1?
i cannot solve without the proper equation lol 
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A police department reports that the probabilities that 0, 1, 2, and 3 burglaries will be reported in a given day are 0.53, 0.40
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The mean of the probability distribution is given by the expected value given by

E(x)=\sum xp(x) \\  \\ =0(0.53)+1(0.40)+2(0.05)+3(0.02) \\  \\ =0.40+0.10+0.06=0.56

The variance of the probability distribution is given by

Var(x)=(x-\bar{x})^2p(x) \\  \\ =(0-0.56)^2(0.53)+(1-0.56)^2(0.40)+(2-0.56)^2(0.05)\\+(3-0.56)^2(0.02) \\  \\ =(-0.56)^2(0.53)+0.44^2(0.40)+1.44^2(0.05)+2.44^2(0.02) \\  \\ =0.3136(0.53)+0.1936(0.40)+2.0736(0.05)+5.9536(0.02) \\  \\ =0.166208+0.07744+0.10368+0.119072=0.4664

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\sigma(x)=\sqrt{Var(x)} \\  \\ =\sqrt{0.4664}=0.683
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babymother [125]

Answer:

x = 45 \ \& \ y = 5

Step-by-step explanation:

The system of linear equations in two variables is ,

\begin{cases} x = 9y \cdots (i)\\ x - 5y = 20\cdots (ii) \end{cases}

We can easily solve out this Question using substitution method . For that , substituting x = 9y from equation (i) to equation (ii) , we have ,

\implies x - 5y = 20 \\\\\implies 9y - 5y = 20 \\\\\implies 4y = 20 \\\\\implies y =\dfrac{20}{4}\\\\\implies\boxed{\boxed{ y = 5 }}

Substituting this value in (i) ,

\implies x = 9y \\\\\implies x = 9\times 5 \\\\\implies \boxed{\boxed{ x = 45 }}

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