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3 years ago

Written equation for y=-2=1 (0,3)

Mathematics

1 answer:

Alika [10]3 years ago

4 0

Is that supposed to be y=-2x+1?
i cannot solve without the proper equation lol

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MAVERICK [17]

It Would Be B x+3/x-3

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3 years ago

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Jack and jill went on their first date to chili's. Their food bill totaled $32.00 plus the 15% tip they needed to pay the waitre

Vlad1618 [11]

A) 15% of $32.00 is $4.80.
B) all together he will be paying $36.80.
i hope this helped, good luck!

5 0

3 years ago

In a study, 36% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop

steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.

i.e. $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

Formula : $P(x=r)=^nC_r p^r q ^ {n-r}$

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

$P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=0.390748$

Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907

5 0

3 years ago

What is the answer for 7.5+2.3y-y

Alexxx [7]

Answer:

9.8

Step-by-step explanation:

7.5+2.3y-y

Subtract y

7.5+2.3

Then Add

9.8

7 0

3 years ago

3. What would the graph of y=x2 + 1 look like?

77julia77 [94]

The answer would be a

6 0

3 years ago

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