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4 years ago

Find the zeros of the function h(x)=x^2-5x-50 by factoring

1 answer:

5 0

$h(x)=x^2-5x-50=x^2-5x-25-25=x^2-25-5x-25\\\\=(x^2-25)-(5x+25)=(x^2-5^2)-5(x+5)\\\\=(x-5)\underline{(x+5)}-5\underline{(x+5)}=(x+5)(x-5-5)=(x+5)(x-10)\\\\Answer:Zeros\ are\ x=-5\ and\ x=10.$

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Step-by-step explanation:

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3 years ago

What is the solution of the system?

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Greetings!

Solve the System, using Elimination:
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Multiply Equation #2 by 2:
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$\left \{ {{4x+2y=18} \atop {4x+6y=30}} \right.$

Eliminate variable x:
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$4y=-12$

Divide both sides by 4:
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Input this value into one of the Equations:
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$4x+2(3)=18$

Simplify:
$4x+6=18$

$(4x+6)+(-6)=(18)+(-6)$

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Divide both sides by 4.
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I hope this helped!
-Benjamin

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3 years ago

Simplify 6^7/6^5 leaving your answer in index form.

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Answer:

Step-by-step explanation: the and is 36.

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3 years ago

What is the quotient?

Anika [276]

Hi!

$-\frac{4}{5}/2$

$-\frac{4}{5} /\frac{2}{1}$

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Explanation: First you had to convert element to fraction is 2=2/1 ,and it gaves us -4/5÷2/1. Then apply to the fraction rules, -4/5 *1/2=-2/5 is the right answer. Hope this helps! And thank you for posting your question at here on Brainly. And have a great day. -Charlie

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3 years ago