Find the zeros of the function h(x)=x^2-5x-50 by factoring

1 answer:

5 0

$h(x)=x^2-5x-50=x^2-5x-25-25=x^2-25-5x-25\\\\=(x^2-25)-(5x+25)=(x^2-5^2)-5(x+5)\\\\=(x-5)\underline{(x+5)}-5\underline{(x+5)}=(x+5)(x-5-5)=(x+5)(x-10)\\\\Answer:Zeros\ are\ x=-5\ and\ x=10.$

You might be interested in

Fine line trucks rents an 18-ft truck for $42 plus 35 cents per mile. Judy needs a truck for one day to deliver a shipment of pl

r-ruslan [8.4K]

Set it up as an equation:
m=miles she can drive

42+.35m=70

Subtract the 42, so

.35m= 28
Divide by .35, so

m=80

She can drive 80 miles

8 0

3 years ago

Plzz helppp!!!!!!!!!1111

Tatiana [17]

AB = CB, AD = CD, DB = BD

3 0

3 years ago

Use distributive property to simplify -7 (- 4x + 8 )

ddd [48]

Answer:

you answer is going to be 17

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

In the equation 4x² - 16x + 12 = 0, the solution is?

ElenaW [278]

X= 3, 1

Hope this helps<3

5 0

3 years ago

Read 2 more answers

Please this is a quizzzz

eduard

Answer:

QR and ST

Explanation:its right

4 0

3 years ago

Read 2 more answers