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3 years ago

BRAINLIEST (try) to show work

Mathematics

2 answers:

kow [346]3 years ago

7 0

Answer:

The domain of the function f(x) i.e. is represented by the graph given is:

−2 < x ≤ 3

Step-by-step explanation:

We know that the domain of some function f(x) is the set of all the possible values of the independent variable i..e set of all the x-values such that the function f(x) is well defined there.

By looking at the graph we see that the domain of f(x) is:

−2 < x ≤ 3

( Since, the f(x) is defined for all the values from -2 to 3 excluding the endpoint -2 since there is a open circle at -2 which represents that the number is not included in the domain i.e. the function is not defined at -2.)

Reika [66]3 years ago

6 0

The domain is the scope of the x values. In this case (-2,-1) is a hole, so x>-2 is one end of the domain, while (3,3) is defined. So the domain using interval notation is (-2,3] which can also be expressed -2 < x ≤ 3, answer option 1.

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The explicit rule for a sequence is given.

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The second one should be it

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3 years ago

PLEASE HELP ME ITS TIMED!!

Sindrei [870]

Answer:

x=40°

Step-by-step explanation:

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2 years ago

Read 2 more answers

What is AE and the perimeter of BCDE? Round your answer to the nearest tenth.

Oliga [24]

Answer:

AE = 43.2 units

Perimeter = 229.2 units

Step-by-step explanation:

Let the side AE be 'x'.

Consider triangles AEB and ADC

Statements Reasons

1. ∠ ABE ≅ ∠ ACD Right angles are congruent.

2. ∠A ≅ ∠A Common angle

Therefore, the two triangles are similar by AA postulate.

Now, for similar triangles, the ratio of their corresponding sides are also proportional to each other. Therefore,

$\frac{AE}{AD}=\frac{AB}{AC}=\frac{BE}{DC}\\\\\frac{AE}{AE+ED}=\frac{AC-BC}{AC}$

Now, plug in the given values and solve for 'x'. This gives,

$\frac{x}{x+72}=\frac{88-55}{88}\\\\88x=33(x+72)\\\\88x=33x+2376\\\\88x-33x=2376\\\\55x=2376\\\\x=\frac{2376}{55}=43.2$

Therefore, AE = 43.2 units

Now, from right angled triangle ABE,

$(AB)^2+(BE)^2=(AE)^2...(Pythagoras\ Theorem)\\\\(33)^2+(BE)^2=(43.2)^2\\\\BE=\sqrt{(43.2)^2-(33)^2}=27.879$

Similarly from right angled triangle ACD,

$CD=\sqrt{AD^2-AC^2}\\\\CD=\sqrt{(72+43.2)^2-88^2}=74.344$

Now, perimeter is the sum of all the sides of a figure. Therefore, the perimeter of BCDE is given as:

Perimeter = BE + ED + CD + BC

Perimeter = 27.879 + 72 + 74.344 + 55 = 229.223 ≈ 229.2 (Nearest tenth)

Therefore, the perimeter = 229.2 units

6 0

3 years ago

Cot 2 2x – 4cot2x + 3 = 0

jeyben [28]

x = 9.21° or x = 22.5°

cot²2x – 4cot2x + 3 = 0

Let cot2x = y

y² - 4y + 3 = 0

Factorizing, we have

y² - y - 3y + 3 = 0

y(y - 1) -3(y - 1) = 0

(y - 1)(y - 3) = 0

y - 1 = 0 or y - 3 = 0

y = 1 or y = 3

Since cot2x = y

cot2x = 1 or cot2x = 3

1/tan2x = 1 or 1/tan2x = 3

tan2x = 1 or tan2x = 1/3

2x = tan⁻¹(1) or 2x = tan⁻¹(1/3)

2x = 45° or 2x = 18.43°

x = 45°/2 or x = 18.43°/2

x = 22.5° or x = 9.21°

So, x = 9.21° or x = 22.5°

Learn more about cotx here:

brainly.com/question/15546709

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3 years ago

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expeople1 [14]

Answer:

y=-x+9

Step-by-step explanation:

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3 years ago