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Romashka-Z-Leto [24]

2 years ago

14

Michael is doing an underwater handstand. His feet are sticking up 0.5 meters above the surface of the water Michael's hands are

1.8 meters directly below his feet. What is the position of Michael's hands relative to the surface of the water?

2 answers:

seropon [69]2 years ago

8 0

0.5-1.8
= -1.3(1.3 metres below the surface of water)

Jlenok [28]2 years ago

6 0

1.3 meters below the surface of the water

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What is the slope of the line that passes through the given points? (6, 2) and (7, 4)

zhannawk [14.2K]

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2 years ago

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Determine whether The given segments have the same length. Justify your answer

Semenov [28]

We know the distance formula is

$\sqrt{ (x_{2}-x_{1})^2+ (y_{2}-y_{1})^2 }$

9)

Here A( -4,2) and B(1,4)

So length of AB

= $\sqrt{(1-(-4))^2+(4-2)^2} =\sqrt{5^2+2^2} =\sqrt{29}$

Also C(2,1)

Length of BC

= $\sqrt{(2-1)^2+(-1-4)^2} =\sqrt{1^2+(-5)^2} =\sqrt{26}$

So we can see that length of AB is not equal to length of BC

11.

Now AB = $\sqrt{29}$

Also C(2,-1) & D(4,4)

Length of CD

= $\sqrt{(4-2)^2+(4-(-1)) ^2} =\sqrt{2^2+5^2} =\sqrt{29}$

Yes AB = CD

5 0

3 years ago

Find an equation of a line that goes through the points (1,6) and (4, -2). Write your answer in the form y=mx + y.

zmey [24]

Answer:

The desired equation is y = (-8/3)x + 26/3.

Step-by-step explanation:

Moving from (1,6) to (4, -2) involves an increase of 3 in x and a decrease of 8 in y. Thus, the slope of the line thru these two points is m = rise / run = -8/3.

Using the slope-intercept form of the eq'n of a straight line and inserting the data given (slope = m = -8/3, x = 4, y = -2), we get:

y = mx + b => -2 = (-8/3)(4) + b, or -2 = -32/3 + b

Multiply all terms by 3 to clear out the fraction:

-6 = -32 + 3b.

Then 26 = 3b, and b = 26/3.

The desired equation is y = (-8/3)x + 26/3.

8 0

2 years ago