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4 years ago

If y = 5x - 2 were changed to y = x - 2, how would the graph of the new

Mathematics

1 answer:

kirill [66]4 years ago

5 0

The slope is different. It went from 5 to one however the y-intercept is the same.

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Find h. 11 in. h = [?] in in. 14 in. PLEASE OH PLEASE HELP ME IM DESPERATE

Sliva [168]

11^2 = h^2 + ( 14/2)^2

11^2 = h^2 + 7^2

121 = h^2 + 49

h^2 = 121 - 49

h^2 = 72

h = √72

4 0

3 years ago

The indicated function y1(x) is a solution of the associated homogeneous equation. Use the method of reduction of order to find

9966 [12]

Answer:

The particular integral of given differential equation

$y_{p} = \frac{1}{4} ( x - (\frac{-5}{4} ) (1))$

General solution of given differential equation

$y = y_{c} + y_{p}$

$Y (x) = C_{1} e^{x} + C_{2} e^{4x} + \frac{1}{4} ( x + (\frac{5}{4} ))$

Step-by-step explanation:

Step(i):-

Given Differential equation y'' − 5 y' + 4 y = x

Given equation in operator form

D²y - 5 Dy + 4 y = x

⇒ ( D² - 5 D + 4 ) y =x

⇒ f(D) y = Q

where f(D) = D² - 5 D + 4 and Q(x) = x

The auxiliary equation f(m) =0

m²-5 m + 4 =0

m² - 4 m - m + 4 =0

m ( m -4 ) -1 ( m-4) =0

(m - 1) =0 and ( m-4) =0

m = 1 and m =4

The complementary function

$Y_{c} = C_{1} e^{x} + C_{2} e^{4x}$

Step(ii):-

particular integral

Particular integral

$y_{p} = \frac{1}{f(D)} Q(x) = \frac{1}{D^{2} - 5 D + 4} X$

taking common '4'

$= \frac{1}{4(1 + (\frac{D^{2} - 5 D}{4} ))} X$

$=\frac{1}{4} (1 + (\frac{D^{2} -5D}{4})^{-1} )} X$

applying binomial expression

( 1 + x )⁻¹ = 1 - x + x² - x³ +.....

$=\frac{1}{4} (1 - (\frac{D^{2} -5D}{4}) +((\frac{D^{2} -5D}{4})^{2} -...} )X$

Now simplifying and we will use notation D = $\frac{dy}{dx}$

$=\frac{1}{4} (x - (\frac{D^{2} -5D}{4})x +((\frac{D^{2} -5D}{4})^{2}(x) -...}$

Higher degree terms are neglected

$=\frac{1}{4} (x - (\frac{ -5 D}{4}) x)$

The particular integral of given differential equation

$y_{p} = \frac{1}{4} ( x - (\frac{-5}{4} ) (1))$

Final answer:-

General solution of given differential equation

$y = y_{c} + y_{p}$

$Y (x) = C_{1} e^{x} + C_{2} e^{4x} + \frac{1}{4} ( x + (\frac{5}{4} ))$

4 0

3 years ago

2. ĐỊNH THỨC 2.1. Giải phương trình: 2 3 1 1 2 4 8 0 1 3 9 27 1 4 14 64

Black_prince [1.1K]

Answer:

Step-by-step explanation:

Uhm the third one number 3

8 0

3 years ago

The endpoints of EF¯¯¯¯¯¯¯¯ are E(−4,12) and F(3,15). Find the coordinates of the midpoint M..

Ray Of Light [21]

Answer:

(-1/2, 27/2)

Step-by-step explanation:

Midpoint formula: (x^1 +x^2/ 2, y^1 +y^2/ 2)

(-4 +3 /2, 12+15/ 2) -> (-1/2, 27/2)

5 0

3 years ago

HELP:) please 30 points

svetlana [45]

This isnt 30 points this is 15

7 0

3 years ago