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slamgirl [31]
3 years ago
13

Please help me out!!!!

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
4 0
To find the length of the arc, you want to multiply the circumference of the circle by the fraction of the degrees in a full circle (360°) that the angle creating the arc PQ covers.

The angle of a complete circle is 360°. Since you are given all the angles except for the angle creating the arc PQ, you can subtract your given angles angles from 360° to get your missing angle:
360°-150°-73°-65° = 72°

The angle creating the arc PQ is 72°. That means the fraction of the full circle that the arc takes up/covers is: \frac{72\°}{360\°} =  \frac{1}{5}. The arc is 1/5 the entire arc/circumference of the circle.

Now find the circumference. Remember that the equation for circumference is c = 2 \pi r, where c=circumference and r=radius. You're given that the radius, r = 6.48 in. Plug that into the circumference equation to find the circumference of the circle:
c = 2 \pi r\\
c = 2 \pi (6.48 \: in)\\
c = 12.96\pi \: in

Now multiply the fraction that the arc covers by the circumference. You know the arc is 1/5 the circumference:
\frac{1}{5} \times 12.96 \pi \: in \approx 8.1 \:in

The length of the arc PQ is about 8.1 in.
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Answer:

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KE=FN=\dfrac{KN-EF}{2}=\dfrac{30-6}{2}=12\ units

Consider right triangle KLE. By the Pythagorean theorem,

KL^2=LE^2+KE^2\\ \\15^2=LE^2+12^2\\ \\LE^2=15^2-12^2\\ \\LE^2=225-144=81\\ \\LE=9\ units

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