Answer:
c. paying a price to keep Mowgli alive
Step-by-step explanation:
" 'Listen to Bagheera. The cub can be bought for a price. it is the law' ..."
Answer:
B=9*5=45m²
P=4+5+3=12m
H=9m
Now
S.A=P*H+2B=12*9+2*45=198m²
V=BH=45*9=405m³
here
B:base area of rectangle
P=perimeter of triangle
H=length of rectangle
S.A=surface area
V=Volume
Step-by-step explanation:
(25)^(-0.25) / (25)^(0.25)
= (25)^(-0.5)
= (5)^(-1)
= 1/5 = 0.2.
Answer by JKismyhusbandbae: Bowler 2 as well has a higher maximum score. While Bowler 1 is less by almost 20 points.
you can use the formula for sample means:
[/tex]
where m stands for a value of the sample mean.
We are looking for the value, specifically for its two borderline values: 70 and 80
and their cumulative probabilities, p(z(80)) and p(z(70)). The difference p(z(80))-p(z(70))
will give the probability that m falls in the interval [70,80]
So let's get cracking at it:
![z(70) = \frac{70-75}{5 / \sqrt{64}} = -8](https://tex.z-dn.net/?f=z%2870%29%20%3D%20%5Cfrac%7B70-75%7D%7B5%20%2F%20%5Csqrt%7B64%7D%7D%20%3D%20-8)
![z(80) = \frac{80-75}{5 / \sqrt{64}} = 8](https://tex.z-dn.net/?f=z%2880%29%20%3D%20%5Cfrac%7B80-75%7D%7B5%20%2F%20%5Csqrt%7B64%7D%7D%20%3D%208)
These are very large values of z. You may notice that any z-table online won't even bother covering range that high - the probabilities for these values are virtually 0 (in the neg case) 1 (in the pos case).
This means that numerically the probability of the sample mean of 64 samples falling within the range of 1 standard deviation is very close to 1
So the answer choice should be 1.0