Answer:
They have the same x-value
f(x) has the greater minimum
Step-by-step explanation:
To find the vertex of a second degree equation, in this case the minimum value, we can use the following equation:
x = -b / 2a
Remember that a second degree equation has the following form:
ax^2 + bx + c
so a = 1, b = -8 and c = 7. Now you have to substitute in the previous equation
x = - (-8) / 2(1)
x = 8 / 2
x = 4
This means that the two functions have the same x-value.
The y value of f(x) would be
f(4) = (4)^2 - 8(4) + 7
f(4) = 16 - 32 + 7
f(4) = -9
So the vertex, or minimun value of f(x) would be at the point (4, -9).
The vertex, or minimun value of g(x) is at the point (4, -4).
So f(x) has a minimum value of -9 and g(x) a minimum value of -4.
1/5n - 12 = -7
or you can say
n/5 - 12 = -7
then if you solve...
n/5 - 12 = -7
+12 +12
n/5 = 5
times 5 on each side
n = 25
300^2 + 500^2 = c^2
9000 + 250000=c^2
340000=c^2
sqrt (340000) = c
c = 583
300 + 500 + 583 = 1383
1380 is the perimeter
Answer:
Step-by-step explanation:
<u>Equation of the Quadratic Function</u>
The vertex form of the quadratic function has the following equation:
Where (h, k) is the vertex of the parabola that results when plotting the function, and a is a coefficient different from zero.
The graph provided in the question, assumed as a parabola, has two clear points:
The vertex, located at (-2,-3)
The point (-1,-6)
Substituting the coordinates of the vertex, the equation of the function is:
The value of a will be determined by using the other point (-1,-6):
Operating:
Solving:
a=-3
The equation of the graph is:
5/2 in improper fraction,2.5 in decimal
