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3 years ago

Find the median, mode, and range for

1 answer:

7 0

To find the median we put the numbers from least to greatest, and cross out the smallest number with the biggest number, until we can't any longer.
54/96, 55/95, 60/89, 66/88, 69/83, 72/82, 73/75, 74/75.
Since we ended with 74 and 75, pick the decimal number that's in between those two numbers, 74.5.
74.5 is your median.
The mode is the number that's most frequent.
There are two 75's, so 75 is your mode.
Range is the difference of the highest number and the lowest number.
96-54=42.
The range is 42.

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Use the Law of Cosines to find the values of x and y. (PLEASE HELPPP!!!!)

vredina [299]

Answer:

$x = 49.8^\circ\\y = 54.6^\circ$

Step-by-step explanation:

Kindly refer to the image attached in the answer region for labeling of triangle.

AB = 16

BC = 19

AC = 15

$\angle ABC = x^\circ\\\angle ACB = y^\circ$

We have to find the angles x and y i.e. $\angle B \text{ and }\angle C$ .

Formula for cosine rule:

$cos B = \dfrac{a^{2}+c^{2}-b^{2}}{2ac}$

Where

a is the side opposite to $\angle A$ ,

b is the side opposite to $\angle B$ and

c is the side opposite to $\angle C$ .

$\Rightarrow cos x = \dfrac{19^{2}+16^{2}-15^{2}}{2 \times 19 \times 16}\\\Rightarrow cos x = \dfrac{392}{608} \\\Rightarrow x = 49.8^\circ$

Similarly, for finding the value of y:

$cos C = \dfrac{a^{2}+b^{2}-c^{2}}{2ab}\\\Rightarrow cos y = \dfrac{19^{2}+15^{2}-16^{2}}{2 \times 19 \times 15}\\\Rightarrow cos y = \dfrac{330}{570}\\\Rightarrow y = 54.6^\circ$

Hence, the values are:

$x = 49.8^\circ\\y = 54.6^\circ$

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3 years ago

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