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Zarrin [17]
3 years ago
12

Before sending track and field athletes to the Olympics, the U.S. holds a qualifying meet.

Mathematics
2 answers:
Leto [7]3 years ago
8 0

Answer:

A

Step-by-step explanation:

I took the test just for you

elena55 [62]3 years ago
5 0
A cause the guy above me said it
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I am pretty sure the answer is A

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Whath percentage of 1m is 76cm
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3 years ago
Y=4x+8x, Solve for x.<br><br> It's x=y/12, I just need to know how to work it out.
Scrat [10]

Step-by-step explanation:

<h2>Answer:-</h2>

\tt{y = 4x+8x}

First, we need to add up the x.

We know that 4+8 = 12, so

\tt{4x+8x=12x}

Now, equating it to y,

\tt{y = 12x}

Now, if I multiply \tt{\dfrac{1}{12}} on both sides,

I get,

\tt{\dfrac{y}{12}= \dfrac{\cancel{12}x}{\cancel{12}}}

Now, as 12 got cancelled , I got the final answer as

\boxed{\tt{x =\dfrac{y}{12}}}

Hope it helps :)

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3 years ago
Researcher Sandy Beach found a correlation coefficient of +2.3 between variables X and Y. She is thrilled because that correlati
tia_tia [17]
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7 0
3 years ago
A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is
Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

\Delta s = s_2-s_1

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

\Delta x = x_2-x_1

So we can use the given points P1:(x_1,y_2)  \text{  and  } P_2: (x_2,y_2) on the displacement formula

\Delta x = 15-4\\\Delta x = 11

In the same manner we can look at the y components of those points to find the vertical displacement

\Delta y = 17-8\\\Delta y =9

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

\tan(\theta) = \cfrac{\Delta y}{\Delta x}

Solving for the angle we get

\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)

Replacing values

\theta = \tan^{-1}\left(\cfrac{9}{11}\right)

Which give us

\theta = 39.3^\circ

So the projection angle is 39.3 degrees.

7 0
3 years ago
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