Step 1: Write out the function given
![f(x)=3x^2-x](https://tex.z-dn.net/?f=f%28x%29%3D3x%5E2-x)
Step 2: Interprete the question given
![\sum ^5_{k\mathop=1}f(\frac{k}{2})](https://tex.z-dn.net/?f=%5Csum%20%5E5_%7Bk%5Cmathop%3D1%7Df%28%5Cfrac%7Bk%7D%7B2%7D%29)
The question requested we find the summation of the first five terms for f(k/2), when k is 1, 2, 3, 4, and 5
Step 3: Find the expression for f(k/2)
![\begin{gathered} f(\frac{k}{2})=3(\frac{k}{2})^2-\frac{k}{2} \\ =\frac{3k^2}{4}-\frac{k}{2} \\ =\frac{3k^2-2k}{4} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20f%28%5Cfrac%7Bk%7D%7B2%7D%29%3D3%28%5Cfrac%7Bk%7D%7B2%7D%29%5E2-%5Cfrac%7Bk%7D%7B2%7D%20%5C%5C%20%3D%5Cfrac%7B3k%5E2%7D%7B4%7D-%5Cfrac%7Bk%7D%7B2%7D%20%5C%5C%20%3D%5Cfrac%7B3k%5E2-2k%7D%7B4%7D%20%5Cend%7Bgathered%7D)
![\begin{gathered} =\frac{3(1)^2-2(1)}{4}+\frac{3(2)^2-2(2)}{4}+\frac{3(3)^2-2(3)}{4}+\frac{3(4)^2-2(4)}{4}+\frac{3(5)^2-2(5)}{4} \\ =\frac{1+8+21+40+65}{4} \\ =\frac{135}{4} \\ =33.75 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%3D%5Cfrac%7B3%281%29%5E2-2%281%29%7D%7B4%7D%2B%5Cfrac%7B3%282%29%5E2-2%282%29%7D%7B4%7D%2B%5Cfrac%7B3%283%29%5E2-2%283%29%7D%7B4%7D%2B%5Cfrac%7B3%284%29%5E2-2%284%29%7D%7B4%7D%2B%5Cfrac%7B3%285%29%5E2-2%285%29%7D%7B4%7D%20%5C%5C%20%3D%5Cfrac%7B1%2B8%2B21%2B40%2B65%7D%7B4%7D%20%5C%5C%20%3D%5Cfrac%7B135%7D%7B4%7D%20%5C%5C%20%3D33.75%20%5Cend%7Bgathered%7D)
Hence, the answer is 33.75
The answer is B because if you have 10000 hours you subtract by 3000 and it’s equals b
Forgive me if I’m wrong. 25?
Answer: i divided AD And the answer is BDC
Step-by-step explanation:
Answer:
y is 8 if you count towards the right side of the screen you will figure out that y is 8 followed by 9 leading you to 10, therefore x is 11.
I hope this helps