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zzz [600]
3 years ago
15

Lily buys a sweater that is on sale for $42, which is 75% of the original price of the sweater. What was the original price of t

he sweater?
a. $168
b. $31
c. $56
d. $73
Mathematics
2 answers:
meriva3 years ago
5 0
So first sivid 42 by 3 to get 14. Then multiply 14 by 4 to get 56. So the answer is C
Evgen [1.6K]3 years ago
4 0
C) $56 because is/of=%/100 so  
42/?=75/100
cross multiply
get 4200
thendivide 4200 by 75 to get 
C) $56
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I=prt,for p please show step by step for this variable
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Answer:

p = \dfrac{I}{rt}

Step-by-step explanation:

I = prt

Switch sides.

prt = I

We are solving for p. We want p alone on the left side. p is being multiplied by r and t, so we divide both sides by r and t.

\dfrac{prt}{rt} = \dfrac{I}{rt}

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Which number is a solution of a² +4= 6a – 1?<br> 07<br> 6<br> 7<br> 8
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Answer:

a=1 or a=5

Step-by-step explanation:

a^{2}+4=6a−1

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a^{2}+4−(6a−1)=6a−1−(6a−1)

a^{2}−6a+5=0

Step 2: Factor left side of equation.

(a−1)(a−5)=0

Step 3: Set factors equal to 0.

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The combined average weight of an okapi and a llama is 450450 kilograms. The average weight of 33 llamas is 190190 kilograms mor
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Answer:

Okapi 290 kg

Llama 160 kg


Step-by-step explanation:

Let weight of each llama be  l

Let weight of each okapi be  o


<em>Given, combined weight of 1 okapi and 1 llama is 450, we can write:</em>

<em>l+o=450</em>

<em>Also, average weight of 3 llama is 190 more than the average weight of 1 okapi, thus we can write:</em>

<em>3l-190=o</em>


Now, substituting 2nd equation into 1st equation, we can solve for weight of 1 llama:

l+o=450\\l+(3l-190)=450\\l+3l-190=450\\4l=450+190\\4l=640\\l=\frac{640}{4}=160


Each llama weights 160 kg, now using this and plugging into 2nd equation, we get weight of 1 okapi to be:

o=3l-190\\o=3(160)-190\\o=290

Each okapi weigh 290 kg

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