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3 years ago

Which sign makes the statement true? -3 ? |3| is it greater than, less than, or equal to?

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

8 0

-3<3

have an amazing day <3

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Tpy6a [65]

It's 2.5 bc it goes up by 2.5 everytime

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3 years ago

Rewrite this expression using a positive exponent.<br> -7<br> 5

Sergio [31]

Answer:

1/5^7

Step-by-step explanation:

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3 years ago

Read 2 more answers

The raitio in simplest form 12:3

pychu [463]

Answer:

4:1

Step-by-step explanation:

you can take the smaller number and divide it by the larger number in this ratio, and the lowest number that you can have is a 1 so this is the only answer that makes any sense.

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3 years ago

(2x + 3y) + (4x - 3y) = 11+(-5)

Maurinko [17]

Answer:

The correct option should have been $6x=6$ .

Step-by-step explanation:

Given the expression

$\left(2x\:+\:3y\right)\:+\:\left(4x\:-\:3y\right)\:=\:11+\left(-5\right)$

solving the expression

$\left(2x\:+\:3y\right)\:+\:\left(4x\:-\:3y\right)\:=\:11+\left(-5\right)$

Remove parentheses: (a) = a

$2x+3y+4x-3y=11-5$

Group like terms

$3y-3y+2x+4x=11-5$

Add similar elements

$6x=6$

It is clear that not a single given option is $6x=6$ . It means no option is correct. It seems you mistyped the correct options.

The correct option should have been $6x=6$ .

3 0

3 years ago

Sketch the equilibrium solutions for the following DE and use them to determine the behavior of the solutions.

GREYUIT [131]

Answer:

$y=\dfrac{1}{1-Ke^{-t}}$

Step-by-step explanation:

Given

The given equation is a differential equation

$\dfrac{dy}{dt}=y-y^2$

$\dfrac{dy}{dt}=-(y^2-y)$

By separating variable

⇒ $\dfrac{dy}{(y^2-y)}=-t$

$\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-dt$

Now by taking integration both side

$\int\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-\int dt$

⇒ $\ln (y-1)-\ln y=-t+C$

Where C is the constant

$\ln \dfrac{y-1}{y}=-t+C$

$\dfrac{y-1}{y}=e^{-t+c}$

$\dfrac{y-1}{y}=Ke^{-t}$

$y=\dfrac{1}{1-Ke^{-t}}$

from above equation we can say that

When t will increases in positive direction then $e^{-t}$ will decreases it means that ${1-Ke^{-t}}$ will increases, so y will decreases. Similarly in the case of negative t.

4 0

3 years ago

Which sign makes the statement true? -3 ? |3| is it greater than, less than, or equal to?​

Which sign makes the statement true? -3 ? |3| is it greater than, less than, or equal to?