Answer:
u = 47
I would explain but some people can't read
4. Change the sign of the integer
In all these expressions you have a power of a power.
You can solve them simply multiplying the exponents.
Remember that any quantity raised to the zero is equal to 1.
.
11) (n^4)^8 = n^(4×8) = n^32
13) (q^10)^10 = q^(10×10) = q^100
15) (x^3)^-5 = x^[3×(-5)] = x^(-15)
17) (z^8)^0z^5 = z^(8×0) z^5 = z^0 z^5 = 1×z^5 = z^5
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19) (c^3)^5(d^3)^0 = c^(3</span>×5) d^(3×0) = c^15 d^0 = c^15×1 = c^15
Answer:
1) The student didn't add copper sulfate but instead he added calcium carbonate.
2) The heated solution should be left to get bigger crystals and should not be instantly allowed to evaporate.
3) He should use copper carbonate not calcium carbonate.
4) Sulfuric acid was added instead of hydrochloric acid.
5) Add solid excessively so that all of the acid is retained.
6) Filter the solution to remove unreacted solid.
7) Heat gently, so the crystals will start to appear.
