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There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Answer:
There are now 6.5 ounces in the new bag.
Step-by-step explanation:
To solve this question, take 30% of 5 and add it to the original amount of 5
30% = 0.30
5 * 0.30 = 1.5
5 + 1.5 = 6.5 ounces of candy.
Hope this helps!
Answer:
Hope it helps...
Step-by-step explanation:
