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olga nikolaevna [1]
3 years ago
15

Solve the equation for x. 1/4 (2x + 8) = −16

Mathematics
1 answer:
tia_tia [17]3 years ago
3 0

1/4 (2x+8)= -16

•Multiply both sides of the equation by 4

2x + 8= -64

•Move constant time the right side and change it’s sign

2x = -64 -8

•Calculate the difference

2x = -72

•Divide both dudes by 2

X= -36
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I need help with finding the sum of (x^4 + 2x^3 - 7x - 9) + (x^5 - 2x^4 + 8x + 18) in standerd form
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This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
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Step-by-step explanation:

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8 = 8 λ y                      ----  ------2

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From equation 1 ,2 and 3

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4\times \dfrac{1}{\lambda^2 }+4\times \dfrac{1}{\lambda^2 }+4\times \dfrac{1}{(2\lambda)^2 }=36

\dfrac{4}{\lambda^2 }+ \dfrac{4}{\lambda^2 }+ \dfrac{1}{\lambda^2 }=36

So the value of λ is

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When λ = 1/2

x = 1 / λ   , y=1 / λ   ,  z= 1 /2 λ

x= 2 , y = 2 , z=1

So

f(x, y, z) = 8 x + 8 y + 4 z

f(2, 2, 1) = 8 x 2 + 8 x 2 + 4 x 1

f(2, 2, 1) =36

When λ = - 1/2

x = 1 / λ   , y=1 / λ   ,  z= 1 /2 λ

x= - 2 , y = - 2 , z= - 1

So

f(x, y, z) = 8 x + 8 y + 4 z

f(-2, -2, -1) = 8 x (-2) + 8 x (-2) + 4 x (-1)

f(-2, -2, -1) = - 36

The maximum value= 36

Minimum value = - 36

7 0
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