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Rasek [7]
2 years ago
6

HELLPP MEMMMEMEMEE pls

Mathematics
1 answer:
-Dominant- [34]2 years ago
4 0

Answer:

60

Step-by-step explanation:

Look at the attachment

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The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
3 years ago
estimate 0.037854921 to the nearest hundredth express your answer as a single digit times a power of 10
Vilka [71]

To solve this problem you must apply the proccedure shown below:

1. Let's round the value to the nearest hundredth. As you can see, the digit 8 is in the thousandths place and is greater than 5, therefore, you must round up to 0.038.

2. Now express the value as a single digit times a power of 10, as following:

38x10^{-3}

Therefore, the answer is: 38x10^{-3}

6 0
2 years ago
Read 2 more answers
1.6 × 1.6 × 1.6 × 1.6
beks73 [17]

1.6 × 1.6 × 1.6 × 1.6 = 6.5536

3 0
3 years ago
Solve for x: -1/2(-4+2x) = -6 - 4x
antiseptic1488 [7]
-\dfrac{1}{2}(-4+2x)=-6-4x\ \ \ \ \ |multiply\ both\ sides\ by\ (-2)\\\\-4+2x=12+8x\ \ \ \ |add\ 4\ to\ both\ sides\\\\2x=16+8x\ \ \ \ \ |subtract\ 8x\ from\ both\ sides\\\\-6x=16\ \ \ \ \ |divide\ both\ sides\ by\ (-6)\\\\x=-\dfrac{16}{6}\\\\x=-\dfrac{8}{3}\\\\\boxed{x=-2\frac{2}{3}}
5 0
3 years ago
1. Find the missing side length.
Anon25 [30]
The first one is b=75the second one is c= 15Hope this helps!

8 0
2 years ago
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