If the function m(x) has the point (5,2) on its graph name a point that would be on the function m(5x).

Mathematics

1 answer:

Law Incorporation [45]3 years ago

6 0

$\bf \begin{array}{|cc|ll} \cline{1-2} x&m(x)\\ \cline{1-2} 5&2\\ 5x&\\ 5(5)& \bf 25 &\\ \cline{1-2} \end{array}$

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Write an equation of the line that passes through (2,-4) and (0,4)

LenKa [72]

Answer:

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step 2. find the slope m. m = (y2 - y1)/(x2 - x1) = (4 - (-4))/(0 - 2) = 8/-2 = -4.

step 3. y - (-4) = -4(x - 2) ; y + 4 = -4x + 8.

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2 years ago

Consider two vectors A and B A=14i and B= -4i+8j

DaniilM [7]

Assuming $\mathbf a,\mathbf b\in\mathbb R^3$ , you have

$\mathbf a\cdot\mathbf b=(14)(-4)+(0)(8)=-56$

so

$((\mathbf a\cdot\mathbf b)\,\mathbf i)\cdot\mathbf a=(-56\,\mathbf i)\cdot(14\,\mathbf i)=(-56)(14)=-784$

Next,

$\mathbf a+\mathbf b=(14\,\mathbf i)+(-4\,\mathbf i+8\,\mathbf j)=10\,\mathbf i+8\,\mathbf j$

Then

$(\mathbf a+\mathbf b)\times\mathbf b=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\10&8&0\\-4&8&0\end{vmatrix}=112\,\mathbf k$

$((\mathbf a+\mathbf b)\times\mathbf b)\times\mathbf k=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&112\\0&0&1\end{vmatrix}=\mathbf 0$