I can't read that language but I'll guess it says write a second degree equation then solve for n when d=10.
![10 = \dfrac{n(n-3)}{2}](https://tex.z-dn.net/?f=10%20%3D%20%5Cdfrac%7Bn%28n-3%29%7D%7B2%7D)
![20 = n^2 - 3n](https://tex.z-dn.net/?f=20%20%3D%20n%5E2%20-%203n)
![n^2 - 3n - 20 = 0](https://tex.z-dn.net/?f=n%5E2%20-%203n%20-%2020%20%3D%200)
Answer: n² - 3n - 20 = 0
That doesn't factor so there is no integer n solution.
That means there are no polygons with 10 diagonals.
![n = \frac 1 2(3 \pm \sqrt{89})](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%201%202%283%20%5Cpm%20%5Csqrt%7B89%7D%29)
Answer:
A
Step-by-step explanation:
area of triangle = 1/2*base*height
small triangle = 1/2*4*3 = 6
Big triangle = 1/2*8*6= 24
24/6=4
the big triangle is 4 times the size of the big triangle. so the small triangle would be 1/4 the size. hence D1/4(xyz) answer is A
To be honest I am not sure but maybe 32 because that is half or 96 but I was never really good with scales.
Answer:
Increase (A)
Step-by-step explanation:
If the common ratio is greater than 1, that means the y-value increases as the x-value increases.
If the common ratio is 1, that means the y-value stays the same as the x-value increases.
If the common ratio is between 0 and 1, that means the y-value decreases and approaches 0 ad the x-value increases.
Because the common ratio is greater than 1, the answer is A, increases