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babymother [125]
3 years ago
11

If the function m(x) has the point (5,2) on its graph name a point that would be on the function m(5x).

Mathematics
1 answer:
Law Incorporation [45]3 years ago
6 0

\bf \begin{array}{|cc|ll} \cline{1-2} x&m(x)\\ \cline{1-2} 5&2\\ 5x&\\ 5(5)& \bf 25 &\\ \cline{1-2} \end{array}

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If John has 1107 bars of chocolate and wants to give each of his 10 friends an even amount each, what would each friend get? Wha
Nutka1998 [239]
Divide 1107 by 10, for example:

1107/10= 110.7

The decimal point means the remainder, this means John will only get 7 chocolate bars. 

If You want it split evenly between ALL of them, divide by 1107 by 11, for example: 

1107/11= 100.6, which would leave six bars left, so I think the logical offer would be the first answer I gave you. 

I hope this helped! 
7 0
3 years ago
For 23-25, use the table.
alexandr402 [8]
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7 0
3 years ago
Read 2 more answers
Set of data with 350,000 numbers is normally
Rudiy27

Step-by-step explanation:

given a normal distribution with the given parameters the probability (= the % of the area of the distribution curve) for a number to be between 203 and 1803 is

0.9987

so, 99.87% of all numbers are expected to be in that range.

for 350,000 numbers that means

350,000×0.9987 = 349,545 numbers are expected to be between 203 and 1803.

7 0
1 year ago
Which of these relations on {0, 1, 2, 3} are equivalence relations? Determine the properties of an equivalence re- lation that t
slava [35]

Answer:

The relations that are equivalence relations are a) and c)

Step-by-step explanation:

A relation on a set A is called an equivalence relation if it is reflexive, symmetric, and transitive

We are going to analyze each one.

a){ (0,0), (1,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

b){ (0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3) }

Is not an equivalence relation. Not reflexive: (1,1) is missing, not transitive: (0,2) and (2,3) are in the relation, but not (0,3)

c){ (0,0), (1,1), (1,2), (2,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

d){ (0,0), (1,1), (1,3), (2,2), (2,3), (3,1), (3,2) (3,3) }

Is not an equivalence relation. Not transitive: (1,3) and (3,2) are in the relation, but not (1,2)

e){ (0,0), (0,1) (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3) }

Is not an equivalence relation. Not symmetric: (1,2) is present, but not (2,1)Not transitive: (2,0) and (0,1) are in the relation, but not (2,1)

5 0
3 years ago
Hi I have my answer in I’m just confused and think it’s gonna be wrong so could u guys help me
Masteriza [31]

Answer:

I believe the first one is rotation And the second is ABC= DEF.

Step-by-step explanation:

My geometry is really rusty so I apologize if they’re wrong

8 0
2 years ago
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