Solve for x.

X^2+7x-30<br> Factor the quadratic<br> Show steps

DENIUS [597]

Answer:

(−3)(+10P)

Step-by-step explanation:

in pic

(Hope this helps can I pls have brainlist (crown) ☺️)

6 0

3 years ago

The circle with center O has a minor arc BSA with a length of

tangare [24]

Answer:

D. $\frac{27\pi}{2}$ inches.

Step-by-step explanation:

We have been given that the circle with center O has a minor arc BSA with a length of $3\pi^{2}$ inches. The central angle is 40°.

To find the circumference of circle we will use formula:

$\frac{\text{Central angle}}{2\pi}=\frac{\text{Arc length}}{2\pi r}$ , where $2\pi$ = measure of 360 degrees in radians and $2\pi r$ = circumference of circle.

Let us convert measure of central angle into radians.

$40^{o}=\frac{40*\pi}{180} =\frac{2\pi}{9}$

Upon substituting our given value in the formula we will get,

$\frac{\frac{2\pi}{9}}{2\pi}=\frac{\frac{3\pi}{2}}{2\pi r}$

$\frac{2\pi}{18\pi}=\frac{3\pi}{4\pi r}$

$\frac{1}{9}=\frac{3}{4r}$

Cross multiplying we will get,

$4r=27$

$r=\frac{27}{4}$

Hence, the radius of our circle is 27/4 inches.

Since the circumference of circle is $2\pi r$ . Upon substituting $r=\frac{27}{4}$ we will get,

$2\pi r=2\pi* \frac{27}{4}=\frac{27\pi}{2}$

Therefore, circumference of our given circle will be $\frac{27\pi}{2}$ inches and option D is the correct choice.

6 0

3 years ago

A scatter plot is shown below: A graph shows numbers from 0 to 10 on the x axis at increments of 1 and the numbers 0 to 15 on th

Mrrafil [7]

Answer:

B (0, 14) and (10, 1)

Step-by-step explanation:

Option A: (0, 14) and (10, 14)

Equation of line using two point slope form .

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

$(x_1,y_1)=(0,14)$

$(x_2,y_2)=(10,14)$

Substitute values in formula :

$y-14=\frac{14-14}{`10-0}(x-0)$

$y-14=0(x-0)$

$y=14$

Option B : (0, 14) and (10, 1)

Equation of line using two point slope form .

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

$(x_1,y_1)=(0,14)$

$(x_2,y_2)=(10,1)$

Substitute values in formula :

$y-14=\frac{1-14}{`10-0}(x-0)$

$y-14=\frac{-13}{10}(x-0)$

$y=\frac{-13}{10}x+14$

Option C: (0, 7) and (7, 0)

Equation of line using two point slope form .

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

$(x_1,y_1)=(0,7)$

$(x_2,y_2)=(7,0)$

Substitute values in formula :

$y-7=\frac{0-7}{`7-0}(x-0)$

$y-7=\frac{-7}{7}(x)$

$y= -x+7$

Option D: (0, 7) and (3, 0)

Equation of line using two point slope form .

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

$(x_1,y_1)=(0,7)$

$(x_2,y_2)=(3,0)$

Substitute values in formula :

$y-7=\frac{0-7}{`3-0}(x-0)$

$y-7=\frac{-7}{3}(x)$

$y=\frac{-7}{3}(x)+7$

Now after plotting all the lines of given options on the graph of scatter plot we can see that the blue line $y=\frac{-13}{10}x+14$ of Option B the is the line of best fit for this scatter plot Since it is covering almost all ordered pairs of scatter plot.

Hence two ordered pairs can be joined to best draw the line of best fit for this scatter plot are (0, 14) and (10, 1)

Option B is correct.