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Elan Coil [88]
2 years ago
13

Helpppppppppppppppppp​

Mathematics
2 answers:
Bumek [7]2 years ago
8 0

Answer:

C, 2/5

Step-by-step explanation:

<u>.</u>

frutty [35]2 years ago
5 0

Answer:

1/5 is the answer because it will land on a fifth of the circle

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How many solutions does the polynomial equation ( x+8)2( x-1) = 0
Olin [163]

Answer:

-8 and 1

Step-by-step explanation:

8 0
3 years ago
Containers A (6cm, 5cm, 4cm), B (5cm, 4cm, 3 cm) and C (3cm, 3cm, 2 cm) are three rectangular containers. At first, container A
motikmotik

Answer:

Step-by-step explanation:

8 0
3 years ago
Percent of change: $25;300% increase
larisa86 [58]
First, find 300% of 25.

Percentages are parts of 100, so divide 300 by 100.

300 / 100 = 3.

So multiply that to 25.

3 * 25 = 75

Add it to 25:

75 + 25 = $100
8 0
3 years ago
Read 2 more answers
A manager records the repair cost for 14 randomly selected dryers. A sample mean of $88.34 and standard deviation of $19.22 are
s2008m [1.1K]

Answer:

Hence the 90% confidence interval estimate of the population mean is (79.24 , 97.44)

Step-by-step explanation:

Given that,  

Point estimate = sample mean = \bar x = 88.34  

sample standard deviation = s = 19.22  

sample size = n = 14  

Degrees of freedom = df = n - 1 = 13  

Critical value =t\alpha /2, df = 1.771

 

Margin of error

E = t\alpha/2,df \times (\frac{s}{\sqrt{n} } )\\= 1.771 \times (19.22 / \sqrt 14)  

Margin of error = E = 9.10  

The 90% confidence interval estimate of the population mean is,  

\bar x - E < \mu < \bar x + E\\\\88.34 - 9.10 < \mu < 88.34 + 9.10\\\\79.24 < \mu < 97.44\\(79.24 , 97.44)

8 0
2 years ago
Suppose that a​ researcher, using data on 150 randomly selected​ bicycles, estimates the OLS​ regression: ModifyingAbove Price w
aliya0001 [1]

Answer:

99% CI for the intercept (b₀) [173.29; 1172.01]dollars

Step-by-step explanation:

Hello!

You have the information of two variables

Y: price of a bycicle (dollars)

X: Weight of a bycicle (kilograms)

The estimated regression equation is

^Y= 672.65 - 1.56X

      (191.4)       (0.28)

Assuming that 191.4 is the estimated standard deviation of the intercept and 0.28 corresponds to the estimated standard deviation of the slope. The statistic you can use to estimate the intercept is a student's t.

99% CI for the intercept (b₀):

b₀ ± tₙ₋₂;1-α * Sb₀

tₙ₋₂;1-α= t₁₄₈;₀.₉₉₅= 2.609

672.65 ± (2.609*191.4)

[173.2874; 1172.0126]dollars

I hope it helps!

6 0
3 years ago
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