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2 years ago

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Mathematics

2 answers:

Bumek [7]2 years ago

8 0

Answer:

C, 2/5

Step-by-step explanation:

frutty [35]2 years ago

5 0

Answer:

1/5 is the answer because it will land on a fifth of the circle

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0.5 L/s = ml/h I need help

qwelly [4]

0.5 L/s = ml/h would be clearer if written as 0.5 L/sec = ml/hr.

Start with 0.5 L/sec:

0.5 L/sec 1000 ml 3600 sec

--------------- * ------------- * ---------------- = 1,000,000 ml/hr

1 1 L 1 hr

8 0

2 years ago

A box of volume 180 m3 with square bottom and no top is constructed out of two different materials. The cost of the bottom is $4

zysi [14]

Answer:

Side of square bottom=6.46 m

Height of box=4.31 m

Step-by-step explanation:

Let s be the side bottom

Height of box=h

Volume of box= $180m^3$

Volume of box= $lbh=s^2h$

$s^2h=180$

$h=\frac{180}{s^2}$

Cost of bottom=$40 per square m

Cost of sides =$30 per square m

Total cost= $C=40s^2+30(4sh)$

$C=40s^2+120s\times \frac{180}{s^2}$

$C(s)=40s^2+\frac{21600}{s}$

Differentiate w.r.t s

$C'(s)=80s-\frac{21600}{s^2}$

$C'(s)=0$

$80s-\frac{21600}{s^2}=0$

$80s=\frac{21600}{s^2}$

$s^3=\frac{21600}{80}=270$

$s=(270)^{\frac{1}{3}}=6.46$

Again,differentiate w.r.t s

$C''(s)=80+\frac{43200}{s^3}$

Substitute s=6.46

$C''(6.46)=80+\frac{43200}{(6.46)^3}=240.2>0$

Hence, the cost is minimum at s=6.46

$h=\frac{180}{s^2}=\frac{180}{(6.46)^2}=4.31$

Side of square bottom=6.46 m

Height of box=4.31 m

5 0

2 years ago

Match each polynomial expression to its additive inverse.

fomenos

Answer:

Step-by-step explanation:

To find the additive inverse of polynomial expression, flip the sign of each term.

6x² ----> -6x²

-x -----> +x

-2 -----> +2

Additive inverse:

-6x² + x + 2

6 0

3 years ago

A newspaper reports the following changes in the temperature of a city over 4 days:

Pie

Answer:

The expression to show the average daily change in temperature can be given by :

⇒ $\frac{2.64-0.22-0.35+0.63}{4}$ °C

Step-by-step explanation:

Changes in the temperature of city as reported by newspaper :

Day 1: 2.64° C

Day 2: $-\frac{2}{9}$ °C

Day 3: -0.35°C

Day 4: $\frac{5}{8}$ °C

The average daily change in temperature can be calculated as

⇒ $\frac{2.64-\frac{2}{9}-0.35+\frac{5}{8}}{4}$ °C

The fractions can be written in decimals

⇒ $\frac{2.64-0.22-0.35+0.63}{4}$ °C

⇒ $\frac{2.7}{4}$ °C

⇒ $0.675\°C\approx 0.68$ °C [Average daily change in temperature.]

6 0

3 years ago

Given the following linear function sketch the graph of the function and find the domain and range.

Sonja [21]

Well after graphing the function. The domain and range would be all real numbers as there are no restrictions and the graph will keep on increasing for the X and y values.

6 0

3 years ago

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