Question

Which equation has solutions of 6 and -6?

Answer 1

Answer:

$x^2-36=0$

Step-by-step explanation:

Solution is 6 and -6. Lets check with each option

$x^2-12x+36=0$

$(x-6)(x-6)=0$

x-6=0 so x=6

Solutions are 6 and 6. First option does not gives us solution 6 and -6

$x^2+12x-36=0$. It is not factorable

$x^2+36=0$. It is not factorable

$x^2-36=0$

$(x+6)(x-6)=0$

x-6=0 , so x=6

x+6=0, so x=-6

$x^2-36=0$ is the final answer

Answer 2

Answer:

x^2-36=0

Step-by-step explanation:

x^2-36=0

(x-6)(x+6)