The completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)
<h3>How to factor the polynomial?</h3>
The expression is given as:
2x^2 + 4x + 3xy + 6y
Group the expression into two
[2x^2 + 4x] + [3xy + 6y]
Factor out each group
2x(x + 2) + 3y(x + 2)
Factor out x + 2
(2x + 3y)(x + 2)
Hence, the completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)
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The answer is 3. 3 is the answer.
Using the law of sines, we have
but angles B and C are congruent, so the sine terms cancel and we're left with
<span>So, what you need to take into consideration here is the order of operations. First, you have to multiply 3 by 6 and then do the rest of the question in the order it is written. So, here is how to calculate this: 3 - 3x6 +2 = 3 - 18 + 2 = -15 + 2 = -13. The correct answer is -13.Hope this helps. Let me know if you need additional help!</span><span />
Answer:
LP = 15
Step-by-step explanation:
LM = LP ( isosceles triangle sides will be equal )
10x - 5 = 7x + 1
Transpose to find the value of x
10x -7x = 1 + 5
3x = 6
x = 6/3
x = 2
now put 2 instead of x
10x - 5
10 (2) - 5
20 - 5
15
LP = 15
