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DedPeter [7]
3 years ago
6

Eee help meee it’s due today

Mathematics
1 answer:
wolverine [178]3 years ago
5 0

2) 2/7 divided 1/3 = 6/7

3) 4/9 times 3/8 = 1/6

4) 5/8 times 2/15 = 1/12

5) 1 divided 3/4 = 1 1/3

6) 1/8 times 8 =1/64

7) 2 1/4 times 1/6 = 3/8

8) 5/8 times 2 2/3 = 1  2/3

9) 1  1/8 times 4 = 4  1/2

10) 2 1/5 divided 11 = 1/5

11) 4 1/2 times 1 1/3 =6

12) 2 1/7 divided 3 3/7

13) 2 2/9 times 7 = 16

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Look at the picture
KATRIN_1 [288]

Answer:

C.

Step-by-step explanation:

use the pythogorean theorem a^2 + b^2 = c^2

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2 years ago
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Find the distance between the ordered pairs. (6, 4) and (-3, 4)​
seropon [69]

Answer: = 9

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Please help slope!!!!!!!!!!!!!
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Answer:

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Step-by-step explanation:

5 0
2 years ago
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In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.
Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

                                     AD+DB=3

                                       x+DB = 3

                                        DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

BC^{2} = DB^{2} +CD^{2}

BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}

BC^{2} =(3-x)^{2} +2

Since given AD=BC,let us plugin BC=x in above step.

x^{2} =(3-x)^{2} +2

x^{2} =9-6x+x^{2} +2

6x=11

x=\frac{11}{6}

Now we know AD=x=\frac{11}{6} and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

AC^{2} =AD^{2} +DC^{2}

AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}

AC^{2} =\frac{193}{36}

AC=\sqrt{\frac{193}{36} } = 2.315cm

3 0
3 years ago
A cone has a radius of 4 units and a height of 6 units.
Usimov [2.4K]
We know, Volume of a Cylinder = πr² h/3
v = 3.14 * 4² * 6/3
v = 3.14 * 16 * 2
v = 100.48 

In short, Your Answer would be Option B

Hope this helps!
7 0
3 years ago
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