This can be written as (x+4)(x+4)
Multiply everything in the second parenthesis by the x.
x^2 + 4x
Multiply everything in the second parenthesis by 4.
4x + 16
Add these two equations together.
x^2 + 4x + 4x + 16
Combine like terms.
x^2 + 8x + 16
Hope this helps!
The answer to this problem is false.
Answer:
Graph A
Step-by-step explanation
The problem: y=2x^2+8x+3
1) You will need to determine the direction of the parabola, If a > 0 then the parabola opens upward, if a < 0 then the parabola opens downward.
2) If when doing this you get an imaginary solution, you would have no x intercepts. The first thing you need to do is find the x intercepts, you can do this by plugging in 0 for y, so this would give you 0=2x^2+8x+3. Once you have this you start by subtracting 3 from both sides, dividing 8 from both side, etc. (If you would like me to elaborate don't hesitate to ask!)
3) To find the graphs y intercept you plug in 0 for x, which gives you y=2(0)^2+8(0)+3, you do the same thing you did during the previous step for y. (Once again, I am willing to elaborate further if you need!)
4) You then need to find the vertex (h,k)
To find h: h= -b/2a
To find k: k = a(h)2 + b(h) + c
5) Once you've worked through this you can graph the point!
Hope this helped!
When c = -3,
-3c² + c - 2c = -3c² - c
= -3(-3)² - (-3)
= -24
