True, as 93 divided by 3 is 31; a whole number :)
Answer:
124.4
Step-by-step explanation:
Perimeter of ∆HIJ = IJ + HJ + HI
IJ = 40
HJ = 37.6
HI = ?
Let's find HI
∆HIJ and ∆EFG are similar. Since they have equal corresponding angles. Therefore, the ratio of their corresponding sides would be equal.
Thus:
EF/HI = FG/IJ
EF = 117 (given)
HI = ?
FG = 100 (given)
IJ = 40 (given)
Plug in the values
117/HI = 100/40
117/HI = 2.5
117 = HI*2.5
117/2.5 = HI
HI = 46.8
✔️Perimeter of ∆HIJ = IJ + HJ + HI
= 40 + 37.6 + 46.8
= 124.4
1/8 is the answer when you subtract 4/8from 5/8
Let x ft be the lenght of the fence and y ft be the width of the fence.
1. The length of the habitat should be at least 80 feet, then

2. The perimeter of the habitat should be no more than 300 feet. The perimeter of the fenceis 2x+2y ft, then

3. The system of inequalities that represent the model is

The graph of these inequalities is attached.
Two possible solutions are
- x=100 ft, y=20 ft (100≥80 and 2·100+2·20=240≤300);
- x=110 ft, y=30 ft (110≥80 and 2·110+2·30=280≤300).
Answer:
A) Histogram
Step-by-step explanation:
A) The first step would be to look at the purpose and use for each type of plotting method;
Dot Plot: Used to represent the distribution of data (for ex; #of Strawberries, Blueberries, and Raspberries.
Histogram: A histogram is used to summarize discrete or continuous data. In other words, it provides a visual interpretation of numerical data by showing the number of data points that fall within a specified range of values
Box Plot: Summerizes a set of data measured on an interval scale.
Best choice: Histogram- The reason why a histogram is the best representation of the student quartiles is because a histogram is used to summarize <u>discrete </u>or <u>continuous data</u>, and the given data is <u>discrete</u>
B)
To create your histogram you first have to create a frequency table like the one below;
On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. Label this axis with the type of data shown (Score, etc.)
Draw a bar extending from the lower value of each interval to the lower value of the next interval. The height of each bar should be equal to the frequency of its corresponding interval.
That's how it's done!