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seraphim [82]
3 years ago
11

A meteorologist used the expression below to describe how the temperature changed.

Mathematics
2 answers:
ratelena [41]3 years ago
7 0

Answer:

-5° degrees temperature and decline of 4°

Step-by-step explanation:

The negative sign simply indicates the temperature at the moment while the negative 4 indicates decline in temperature.

ElenaW [278]3 years ago
3 0

Answer:

the answer is B

Step-by-step explanation:

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A high rise apartment building has 15 floors with 26 apartments on each floor.There are 3 kinds of apartments in the building: 1
konstantin123 [22]

Answer:

The number of each kind of apartment in the building is 130  .

Step-by-step explanation:

Given as :

The total number of floor in a building = 15

The number of apartment on each floor = 26

So, The total number of apartment = 26 × 15 = 390

The number of kinds of apartment in the building is 3 ,  i.e 1-bedroom ,               2-bedroom , 3-bedroom

Let The number of each kind of apartment in building = x

So, According to question

The number of each kind of building = \dfrac{\textrm Total number of apartment }{number of kinds of apartment}

or, x = \frac{390}{3}

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3 0
3 years ago
Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin
sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x

7 0
3 years ago
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