What are two consecutive integers that have a sum of -67
1 answer:
Answer:
The two integers are -34,-33
Step-by-step explanation:
x 1st integer
x+1 2nd integer
The sum is -67
x+x+1 = -67
Combine like terms
2x+1 = -67
Subtract 1 from each side
2x+1-1 = -67-1
2x= -68
Divide by 2
2x/2 = -68/2
x = -34
x+1 = -34+1 = -33
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Answer:
c=26
Step-by-step explanation:
So you would use the formula a^2+b^2=c^2
10^2+24^2=c^2
100+576=c^2
C^2=676
c=26
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4x +8 -x + 10 = x+4
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2x= -14
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