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3 years ago

What is the average of 0,1,3,2

1 answer:

3 0

I'm gonna say the average is 1.5 because is the sum of the elements divided by the number of elements.

0+1+3+2=6
6/4= 1.5

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Express your answer in the smallest unit: 338km+ 62km 71m

Alexeev081 [22]

Adding all of the together would be 471... but I need clarification on the problem

8 0

3 years ago

Any proof professionals please help!!!!!!!! We don't drag or drop answers in we have to write them out ourselves!!!! It's worth

shepuryov [24]

Answer:

Below.

Step-by-step explanation:

These reasons will probably be similar to the US conventions but not exactly the same ( I'm using the UK conventions).

1. Given

2. Given.

3, Opposite sides of a parallelogram.

4. Opposite sides of a parallelogram.

5. This side is common to both triangles.

6. The triangles are congruent by 3 equal sides ( I think that is SSS).

5 0

3 years ago

Which of the following functions has a vertical asymptote at x=2, a horizontal asymptote at f(x)=1, and a root at x=−1?

pantera1 [17]

Definitely c but if not my bad

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2 years ago

A new solid is created by cutting a right rectangular prism from a cube. The right rectangular prism has a length

Mila [183]

Volume of solid created = $85m^{3}$ .

<u>Step-by-step explanation:</u>

We have , A new solid is created by cutting a right rectangular prism from a cube. The right rectangular prism has a length of 5 m, a width of 4 m, and a height of 2 m. The side lengths of the cube are 5 m . Volume of solid created = Volume of cube - Volume of rectangular prism

Volume of cube = $side^{3}$

⇒ $Volume1 = side^{3}$

⇒ $Volume1 = 5^{3}$

⇒ $Volume1 = 125m^{3}$

Volume of rectangular prism = $wlh$

⇒ $Volume2 = wlh$

⇒ $Volume2 = 5(4)(2)$

⇒ $Volume2 = 40m^{3}$

Now, Volume of solid created = Volume of cube - Volume of rectangular prism

⇒ Volume of solid created = $Volume1 - Volume2$

⇒ Volume of solid created = $125m^{3} - 40m^{3}$

⇒ Volume of solid created = $85m^{3}$

∴ Volume of solid created = $85m^{3}$ .

8 0

3 years ago

I need help pls on math

Rina8888 [55]

$x^2-x-12=x^2+3x-4x-12=x(x+3)-4(x+3)=(x+3)(x-4)\\\\x^2-2x-8=x^2+2x-4x-8=x(x+2)-4(x+2)=(x+2)(x-4)\\\\4x^2=2x\cdot2x$

$\dfrac{x^2-x-12}{2x}:\dfrac{x^2-2x-8}{4x^2}=\dfrac{x^2-x-12}{2x}\cdot\dfrac{4x^2}{x^2-2x-8}\\\\=\dfrac{(x+3)(x-4)}{2x}\cdot\dfrac{2x\cdot2x}{(x+2)(x-4)}=\dfrac{(x+3)}{1}\cdot\dfrac{2x}{(x+2)}\\\\=\boxed{\dfrac{2x^2+6x}{x+2}}$

4 0

4 years ago