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Licemer1 [7]
3 years ago
9

A rectangle has a length (2x−5) and a width of (x−3) . What is the area of the rectangle?

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
4 0

Answer:

2x² - 11x + 15

Step-by-step explanation:

Find the area of the rectangle by multiplying the length and width together, using FOIL

(2x - 5)(x - 3)

Multiply the first terms:

(2x)(x) = 2x²

Multiply the first term in the parentheses by the last term in the second set of parentheses:

(2x)(-3) = -6x

Multiply the second term in the first set of parentheses by the first term in the second set:

(-5)(x) = -5x

Multiply the last terms:

(-5)(-3) = 15

Add these all together, then add like terms

2x² - 6x - 5x + 15

2x² - 11x + 15

So, the area of the rectangle is 2x² - 11x + 15

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$34,300 loan at 3.5% for 4 months.
cestrela7 [59]

keeping in mind that 4 months is not even a year, since there are 12 months in a year, 4 months is then 4/12 years.

let's assume is simple interest.


\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$34300\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ t=years\to \frac{4}{12}\dotfill &\frac{1}{3} \end{cases} \\\\\\ A=34300\left[ 1+(0.035)\left( \frac{1}{3} \right) \right]\implies A= 34300(1.011\overline{6})\implies A=34700.1\overline{6}

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3 years ago
Isosceles trapezoid ABCD has legs AB and CD and base BC. If AB=5y - 10, BC=6y+2, and CD = 2y+8, find the value of Y.
pishuonlain [190]

Hello from MrBillDoesMath!

Answer:

Choice C    (6)

Discussion:

Since it is an isosceles trapezoid the length of the two legs (i.e.  AB = 5y-10 and CD = 2y+8) are equal.  In other words,

5y - 10 = 2 y + 8

Subtract 2y from each side:

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Now add 10 to each side

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3y + 0 = 18 =>

3y = 18 =>

y = 6


Regards,  

MrB


3 0
3 years ago
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