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Yanka [14]
3 years ago
5

An animal shelter spends $5.00 per day to care for each bird and $7.50 per day to care for each cat. Jayden noticed that the she

lter spent $247.50 caring for birds and cats on Wednesday. Jayden found a record showing that there were a total of 41 birds and cats on Wednesday. How many birds were at the shelter on Wednesday?
Mathematics
1 answer:
Vilka [71]3 years ago
7 0

Answer:

   24 birds

Step-by-step explanation:

Let b represent the number of birds at the shelter on Wednesday. Then the cost of care for the 41 animals is ...

  5b +7.5(41 -b) = 247.50

  -2.5b +307.50 = 247.50 . . . . . simplify

  -2.5b = -60 . . . . . . . . . . . . . . . . subtract 307.50

  b = 24 . . . . . . . . . divide by -2.5

The number of birds at the shelter on Wednesday was 24.

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grandymaker [24]

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Step-by-step explanation:

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Reserved tickets for the football game cost $20 each and general admission tickets cost $12. The total ticket sales brought in $
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3 years ago
A rectangle has an area of 15/100 square unit. The length of the rectangle is 3/10 unit. What is the width of the rectangle?
marysya [2.9K]
Hope this helps. Let me know if you have more questions.

4 0
3 years ago
A business owner opens one store in town A. The equation p(x) = 10,000(1.075) represents the anticipated profit after t years. T
alexgriva [62]
The rigth equation to anticipate the profit after t years is p(t) = 10,000 (1.075)^t

So, given that both store A and store B follow the same equations but t is different for them, you can right:

Store A: pA (t)  10,000 (1.075)^t

Store B: pB(t'): 10,000 (1.075)^t'

=> pA(t) / pB(t') = 1.075^t / 1.075^t'

=> pA(t) / pB(t') = 1.075 ^ (t - t')

And t - t' = 0.5 years

=> pA(t) / pB(t') = 1.075 ^ (0.5) = 1.0368

or pB(t') / pA(t) = 1.075^(-0.5) = 0.964

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Which means that the profit of the store B is about 96% the profit of store A at any time after both stores have opened.


7 0
3 years ago
Read 2 more answers
Which is the value of this expression when p=-2 and q=-1?
saul85 [17]

Answer:

D. 4

Step-by-step explanation:

[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4

8 0
3 years ago
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