Step-by-step explanation:
it may help you to understand
First of all, the modular inverse of n modulo k can only exist if GCD(n, k) = 1.
We have
130 = 2 • 5 • 13
231 = 3 • 7 • 11
so n must be free of 2, 3, 5, 7, 11, and 13, which are the first six primes. It follows that n = 17 must the least integer that satisfies the conditions.
To verify the claim, we try to solve the system of congruences

Use the Euclidean algorithm to express 1 as a linear combination of 130 and 17:
130 = 7 • 17 + 11
17 = 1 • 11 + 6
11 = 1 • 6 + 5
6 = 1 • 5 + 1
⇒ 1 = 23 • 17 - 3 • 130
Then
23 • 17 - 3 • 130 ≡ 23 • 17 ≡ 1 (mod 130)
so that x = 23.
Repeat for 231 and 17:
231 = 13 • 17 + 10
17 = 1 • 10 + 7
10 = 1 • 7 + 3
7 = 2 • 3 + 1
⇒ 1 = 68 • 17 - 5 • 231
Then
68 • 17 - 5 • 231 ≡ = 68 • 17 ≡ 1 (mod 231)
so that y = 68.
Csc^2x-cot^2x=1
Here is why
csc^2x=1+cot^2x
so:
1+cot^2x-cot^2x=1
1=1
Let f(x)=0.

Using the zero-factor property, equate each factor to 0 and then solve for x.

Thus, the zeros of the given function are 6 and -5.
The zeros are the x-coordinate where the graph touches the x-axis.
Thus, the x-coordinates of where the graph touches the x-axis are -5, and 6.
Answer: 6.5%
Step-by-step explanation:
$5.86 -$5.50
=$0.36
We then divide $0.36 by 5.50 =0.065
Multiply by 100 to convert decimal to percentage= 0.065×100
=6.5%