The 5 is in the tens spot and the 8 is in the ones.
Look at chart. Plug in an 8 where it says ones, and the 5 where it says tens. Yeah?
Answer:
(3, 0) and (5, 0)
Step-by-step explanation:
we have

we know that
The x-intercepts are the values of x when the value of y is equal to zero
so
For y=0

The formula to solve a quadratic equation of the form
is equal to

in this problem we have
so

substitute in the formula





so
x=3, x=5
therefore
The x-intercepts are (3,0) and (5,0)
Answer:
28
Step-by-step explanation:
i think hope this helps